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mario62 [17]
3 years ago
11

If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V, the current flowing through the circ

uit is...
A. 60 A.
B. 5 A.
C. 0.2 A.
D. 720 A.
Physics
2 answers:
OlgaM077 [116]3 years ago
8 0

Current = (voltage)/(resistance) = (60 v) / (12 ohms) = 5 amperes  (B)
AnnyKZ [126]3 years ago
7 0
The formula for calculating the current flowing in a circuit is:
I = V /R
Where:
I = current = ?
V = voltage = 60 V
R = resistance = 12 Ohms
I = V /R = 60/ 12 = 5
Therefore, the current flowing through the circuit is 5 A.
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When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin
dusya [7]

Answer:

(a) 5.04 eV (B) 248.14 nm (c) 1.21\times 10^{15}Hz

Explanation:

We have given Wavelength of the light  \lambda = 240 nm

According to plank's rule ,energy of light

E = h\nu = \frac{hc}{}\lambda

E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV

Maximum KE of emitted electron i= 0.17 eV

Part( A) Using Einstien's equation

E = KE_{max}+\Phi _{0}, here \Phi _0 is work function.

\Phi _{0}=E - KE_{max}= 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}

\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }

\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm

Part (C) In this part we have to find the cutoff frequency

\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz

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3 years ago
What is the difference between a low tide and a high tide
Savatey [412]
A high tide means when the water has risen and is higher up(closer to high up land). Low tide is when it’s receded
6 0
2 years ago
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A gyroscope flywheel of radius 3.25 cm is accelerated from rest at 11.6 rad/s2 until its angular speed is 1820 rev/min. (a) What
kati45 [8]

Explanation:

The given data is as follows.

           radius (r) = 3.25 cm,    \alpha = 11.6 rad/s^{2}

Now, we will calculate the tangential acceleration as follows.

          a_{tangential} = \alpha \times r

Putting the given values into the above formula as follows.

         a_{tangential} = \alpha \times r

                      = 11.6 rad/s^{2} \times 3.25 cm

                      = 37.7 rad cm/s^{2}

Thus, we can conclude that the tangential acceleration of a point on the rim of the flywheel during this spin-up process is 37.7 rad cm/s^{2}.

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3 years ago
What is the difference between a measurement and an observation?A. Measurements are made with tools; observations are not.B. Obs
choli [55]

Answer:

A. Measurements are made with tools; observations are not

Explanation:

Measurement: <em>the assignment of numbers or codes according to prior-set rules. </em>

Observation: <em>data from an individual study subject or sampled unit.</em>

Measurement error: <em>differences between "true" answers and what appears on data collection instruments</em>

hope this helps

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3 years ago
Before a star is born, the matter that will become the star exists as a
vazorg [7]

Answer:

The answer is D

Explanation:

I'm too lz to explain everything.

sorry.

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