Answer:
The correct answer is "The rigid body can have rotational and transnational motion, as long as it's transnational and angular accelerations are equal to zero."
Explanation:
A rigid body by definition does not deform when forces act on it. In case of static equilibrium a rigid body cannot have any sort of motion while in case of dynamic equilibrium it can move but with constant velocities only thus having no acceleration weather transnational or angular.
Answer:
a). ![H=2.45m](https://tex.z-dn.net/?f=H%3D2.45m)
b). ![H_{max}=1.94m](https://tex.z-dn.net/?f=H_%7Bmax%7D%3D1.94m)
Explanation:
For the block that stays on the track, its maximal height is attained when all of the kinetic energy is converted to potential energy
a).
The height for the block on the longer track can by find using this equation:
![\frac{1}{2}*m*v_o^2=m*g*H](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_o%5E2%3Dm%2Ag%2AH)
Cancel the mass as a factor in each element in the equation
![H=\frac{v_o^2}{2*g}](https://tex.z-dn.net/?f=H%3D%5Cfrac%7Bv_o%5E2%7D%7B2%2Ag%7D)
![H=\frac{(6.94m/s)^2}{2*9.8m/s^2}](https://tex.z-dn.net/?f=H%3D%5Cfrac%7B%286.94m%2Fs%29%5E2%7D%7B2%2A9.8m%2Fs%5E2%7D)
![H=2.45m](https://tex.z-dn.net/?f=H%3D2.45m)
b).
The other lost some kinetic energy so, use a projectile motion to determine the total height for the other bock:
![E_k=E_p](https://tex.z-dn.net/?f=E_k%3DE_p)
![E_k=m*g*H_1](https://tex.z-dn.net/?f=E_k%3Dm%2Ag%2AH_1)
![E_k=\frac{1}{2}*m*v_o^2-\frac{1}{2}*m*v^2](https://tex.z-dn.net/?f=E_k%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_o%5E2-%5Cfrac%7B1%7D%7B2%7D%2Am%2Av%5E2)
![m*g*H_1=\frac{1}{2}*m*(v_o^2-v^2)](https://tex.z-dn.net/?f=m%2Ag%2AH_1%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2A%28v_o%5E2-v%5E2%29)
Solve to v'
![v^2=v_o^2-2*g*H_1](https://tex.z-dn.net/?f=v%5E2%3Dv_o%5E2-2%2Ag%2AH_1)
![v=\sqrt{v_o^2-2*g*H_1}=\sqrt{(6.94m/s)^2-2*9.8m/s^2*1.25m}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bv_o%5E2-2%2Ag%2AH_1%7D%3D%5Csqrt%7B%286.94m%2Fs%29%5E2-2%2A9.8m%2Fs%5E2%2A1.25m%7D)
![v=4.8m/s](https://tex.z-dn.net/?f=v%3D4.8m%2Fs)
![H_{max}=H_1+\frac{v^2*sin(50)}{2*g}=1.25m+\frac{(4.8m/s)^2*sin(50)}{2*9.8m/s^2}](https://tex.z-dn.net/?f=H_%7Bmax%7D%3DH_1%2B%5Cfrac%7Bv%5E2%2Asin%2850%29%7D%7B2%2Ag%7D%3D1.25m%2B%5Cfrac%7B%284.8m%2Fs%29%5E2%2Asin%2850%29%7D%7B2%2A9.8m%2Fs%5E2%7D)
![H_{max}=1.94m](https://tex.z-dn.net/?f=H_%7Bmax%7D%3D1.94m)
The cabinet is being pulled with 200N and is being rested by a force equal to 200N. That is why it is not being moved.
<span>Although the force of static friction can equal Fk=µs*F=m*g*µs=(30kg)*(9.8m/s^2)*(0.80)=235 N. It is not resisting the 200N force with 235N. Imagine if you pushed something with 200N and it pushed you back with 235N, especially a cabinet. You would think that the cabinet was alive.</span>
Answer:
Pretty sure magnetic waves thank me later bro bro
Answer:
-1786.5J
Explanation:
Temperature 1=T1=25°c
Temperature 2=T2=200°c
Pressure P1=1bar
Pressure P2=0.5bars
T=37°c+273=310k
Note number if moles=1
Recall work done =2.3026RTlogp2/P1
2.3026*8.314*310log(0.5/1)
-1786.5J