Answer:
The answer to your question is ΔP = 1.57 atm
Explanation:
Data
moles = 1
volume = 0.5 L
Temperature = 22°C or 295°K
Pressure = ?
a) Ideal Gas
PV = nRT R = 0.082 atm L / mol°K
-Solve for P
P = nRT/V
P = (1)(0.082)(295)/ 0.5
P = 23.944/ 0.5
P = 47.9 atm
b) Van der Waals
(P + a/v²)(v - b) = RT
- Substitution
(P + 1.345/0.5²)(0.5 - 0.03219) = (0.082)(295)
- Simplification
(P + 5.38)(0.46781) = 24.19
P + 5.38 = 24.19/0.46781
P + 5.38 = 51.71
-Solve for P
P = 51.71 - 5.38
P = 46.33 atm
c) The difference between both Pressures is
ΔP = 47.9 - 46.33
= 1.57 atm
Answer:
Explanation:
a )
From the graph given , energy of reactant = 0
b )
energy of product = -15 kJ
c )
ΔH = energy of product - energy of reactant
= -15 - 0 = - 15 kJ
ΔH is negative so reaction is exothermic .
d ) Activation energy = 25 - 0 = 25 kJ .
e ) Energy released = 15 kJ .
D. Even though the temperature is the same, container B has more thermal energy, since it has more liquid than container A.
<u>Explanation:
</u>
Whenever there is an increase in the volume of the pink liquid, it is due to the increase in temperature.
When the temperature increases, the molecules move farther apart as much as possible.
When the molecules moves apart from each other and collide with each other, so that its kinetic energy also increases, So thermal energy of the container B is more compared to the container A.
Answer:
A. your observations in writing
Explanation:
Descriptive investigation is one of the mode of inquiries in science. It is devoid of the usual collection of data in the field or setting up laboratory experiments to compared variables.
- In descriptive investigation, observations are usually done in writing.
- They are usually common in Astrology.
- Such investigation involves a question without a hypothesis ensuing.
- Tests are usually not carried out in descriptive investigation.
