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Ronch [10]
3 years ago
12

Calculate the theoretical yield of aspirin obtained when 2.0 g of salicylic acid and 5.0 mL of acetic anhydride (density = 1.08

g/mL) are mixed together.(Molar masses: acetic anhydride = 102.1 g/mol; salicylic acid = 138.2 g/mol)If 1.6 g of aspirin were obtained in this experiment, what would be the percentage yield?The melting point of the crude aspirin was reported as 126 °C. What does it indicate about the purity of the product?
Chemistry
1 answer:
blondinia [14]3 years ago
8 0

Answer:

The % yield = 61.3 %

The aspirin is impure, since the melting point was too low

Explanation:

<u>Step 1:</u> Data given

Mass of salicylic acid = 2.0 grams

Volume of acetic anhydride = 5.0 mL ( Density = 1.08 g/mL)

Molar mass of acetic anhydride =102.1 g/mol

Molar mass of salicylic acid = 138.2 g/mol

<u>Step 2:</u> The balanced equation

C7H6O3 + C4H6O3 → C9H8O4 + CH3COOH

<u>Step 3:</u> Calculate moles of salicylic acid

Moles salicylic acid = mass salicylic acid / Molar mass salicylic acid

Moles salicylic acid = 2.0 grams /138.2 g/mol

Moles salicylic acid = 0.0145 moles

<u>Step 4: </u>Calculate moles of acetic anhydride

Mass of acetic anhydride = 1.08 g/mL * 5.0 mL = 5.4 grams

Moles acetic anhydride = 5.4 grams / 102.1 g/mol

Moles acetic anhydride = 0.0529 moles

<u>Step 5</u>: Calculate limting reactant

Mole ratio is 1:1 so since salicylic acid has the smallest number of moles, it's the limiting reactant

Salicylic acid will completely be consumed (0.0145 moles)

Acetic anhydride is in excess. There will 0.0145 moles be consumed.

There will remain 0.0529 -0.0145 = 0.0384 moles of acetic anhydride

<u>Step 6</u>: Calculate moles of aspirin

Since mole ratio is 1:1 there will be produced 0.0145 moles of aspirin

<u>Step 7:</u> Calculate mass of aspirin

Mass of aspirin = 0.0145 moles * 180.158 g/mol

Mass of aspirin =  2.61 grams = theoretical yield

<u>Step 8:</u>  Calculate % yield

% yield = actual yield / theoretical yield

% yield = (1.6 grams / 2.61 grams)*100%

% yield = 61.3 %

Since the melting point of pure aspirin is 138-140, this means that the aspirin was impure. It's possible that the aspirin still has insoluble impurities in it.

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Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

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8 0
3 years ago
1.15 g of a metallic element needs 300 cm3 of oxygen for complete reaction, at 298 K and 1 atm
sashaice [31]
1) Calculate the number of moles of O2 (g) in 300 cm^3 of gas at 298 k and 1 atm


Ideal gas equation: pV = nRT => n = pV / RT


R = 0.0821 atm*liter/K*mol

V = 300 cm^3 = 0.300 liter

T = 298 K

p = 1 atm


=> n = 1 atm * 0.300 liter / [ (0.0821 atm*liter /K*mol) * 298K] = 0.01226 mol


2) The reaction of a metal with O2(g) to form an ionic compound (with O2- ions) is of the type


X (+) + O2 (g) ---> X2O          or   


2 X(2+) + O2(g) ----> X2O2 = 2XO     or


4X(3+) + 3O2(g) ---> 2X2O3


 
In the first case, 1 mol of metal react with 1 mol of O2(g); in the second case, 2 moles of metal react with 1 mol of O2(g); in the third, 4 moles of X react with 3 moles of O2(g)



So, lets probe those 3 cases.


3) Case 1: 1 mol of metal X / 1 mol O2(g) = x moles / 0.01226 mol

=> x = 0.01226 moles of metal X


Now you can calculate the atomic mass of the hypotethical metal:

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That does not correspond to any of the metal with valence 1+


So, now probe the case 2.



4) Case 2:


2moles X metal / 1 mol O2(g) = x / 0.01226 mol


=> x = 2 * 0.01226 = 0.02452 mol


And the atomic mass of the metal is: 1.15 g / 0.02452 mol = 46.9 g/mol


That is similar to the atomic mass of titanium which is 47.9 g / mol and whose valece is 2+.


4) Case 3


4 mol meta X / 3 mol O2 = x / 0.01226 => x = 0.01226 * 4 / 3 = 0.01635 


atomic mass = 1.15 g / 0.01635 mol = 70.33 g/mol


That does not correspond to any metal.


Conclusion: the identity of the metallic element could be titanium.
5 0
3 years ago
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