Question

HELP. I DONT KNOW WHAT TO DO. Barium sulfate, BaSO4, is made by the following reaction.

Answer 1

Answer:

$\boxed{\text{66.95 g BaSO _{4} }}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:         261.34                         233.39

              Ba(NO₃)₂ + Na₂SO₄ ⟶ BaSO₄ + 2NaNO₃

m/g:         75.00

1. Moles of Ba(NO₃)₂

$\text{Moles of Ba(NO _{3})_{2} } = \text{75.00 g} \times \dfrac{\text{1 mol}}{\text{261.34 g}} = \text{0.286 98 mol}$

2. Moles of BaSO₄

The molar ratio is (1 mol BaSO₄/1 mol Ba(NO₃)₂

$\text{Moles of BaSO _{4} }= \text{0.286 98 mol Ba(NO _{3})_{2} } \times \dfrac{\text{1 mol BaSO _{4} }}{\text{1 mol Ba(NO _{3})_{2} }} = \text{0.286 98 mol BaSO _{4} }$

3. Mass of BaSO₄

$\text{Mass of BaSO _{4} } = \text{0.286 98 mol BaSO _{4} } \times \dfrac{\text{233.39 g BaSO _{4} }}{\text{1 mol BaSO _{4} }} = \textbf{66.98 g BaSO _{4} }\\\\\text{The theoretical yield of barium sulfate is } \boxed{\textbf{66.98 g BaSO _{4} }}$