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Answer:
I will assume that “maximum force” implies the constant application of power P = 400 hp (international) to accelerating the vehicle. The force will therefore vary with speed as the vehicle accelerates. I will also assume that all engine energy goes into accelerating the vehicle, rather than rotating elements like its wheels.
In this case the 400 hp (equivalent to 298,280 watts) is applied for time t = 2 seconds. Therefore the kinetic energy of the vehicle is increased by:
ΔKE=Pt=(298,280)(2)=596,560 joules.
The initial kinetic energy is:
KEinitial=12mv2
=(0.5)(1600)(82)=51,200 joules.
Therefore final kinetic energy is:
KEfinal=KEinitial+ΔKE
=51,200+596,560
=647,760 joules
Therefore final vehicle velocity can be found:
KEfinal=12mv2
v=2KEfinalm−−−−−−−−√
=(2)(647,760)1600−−−−−−−−−−−√
= 28.455 m/s
Explanation:
Answer:
0.694 m
Explanation:
Case 1 : When only mass of 2.82 kg is hanged from spring
m = mass hanged from the spring = 2.82 kg
x = stretch caused in the spring = 0.331 m
k = spring constant
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
k (0.331) = (2.82) (9.8)
k = 83.5 N/m
Case 2 : When both masses are hanged from spring
m = mass hanged from the spring = 3.09 + 2.82 = 5.91 kg
x = stretch caused in the spring = ?
k = spring constant = 83.5 N/m
Using equilibrium of force in vertical direction
Spring force = weight of the mass
k x = m g
(83.5) x = (5.91) (9.8)
x = 0.694 m
Answer:
a) Acceleration of runner is 1.33 m/s²
b) Acceleration of motorcycle is 2.85 m/s²
c) The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.
Explanation:
t = Time taken
u = Initial velocity = 0
v = Final velocity
s = Displacement
a = Acceleration
Equation of motion
Acceleration of runner is 1.33 m/s²
Acceleration of motorcycle is 2.85 m/s²
The runner moves 2.94 m
The motorcycle moves 84.21 m
The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.
