Determine the amount of heat (in kj) required to vaporize 1.55 kg of water at its boiling point. for water, δhvap
1 answer:
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Hello!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
Have a nice day!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
Have a nice day!
Answer:
22Ω
Explanation:
Given parameters:
Potential difference = 3.3V
Current = 0.15A
Unknown:
Resistance = ?
Solution:
According to ohm's law, potential difference, current and resistance are related by the expression below;
V = I R
where V is the voltage
I is the current
R is the resistance
3.3 = 0.15 x R
R = = 22Ω