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Ira Lisetskai [31]
3 years ago
15

Using VSEPR model, how is the molecular arrangement about the central atom (molecular geometry) for XeF4?

Chemistry
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

Square planar.

Explanation:

Hello,

In this case, it can be demonstrated that the central atom Xenon in XeF₄ has a sp³d² hybridization which means that its geometry is likely to be octahedral.  Nevertheless Applying by applying the valence shell electron pair repulsion (VSEPR) model to in order to minimize the repulsion among lone pairs, bond pairs and lone pair-bond pairs, we we realize repulsion is actually minimized when lone pairs are anti to one another and the fluorine atoms are in equatorial position, for that reason, the corrected and properly exhibited geometry or molecular arrangement of the compound turns out square planar. You can verify it on the attached picture.

Regards.

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Explanation:

Given that,

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Answer:

1. Theoretical yield = 2.03g

2. Actual yield 1.89g

Explanation:

Let us write a balanced equation. This is illustrated below:

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Therefore, 74g of HCl will produce = (74 x 2)/73 = 2.03g

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Actual yield =?

%yield = Actual yield /Theoretical yield x100

Actual yield = %yield x theoretical yield

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