Answer:
Liquid's index of refraction, n₁ = 1.27
Explanation:
It is given that,
The critical angle for a liquid in air is, 
We have to find the refractive index of the liquid. Critical angle of a liquid is defined as the angle of incidence in denser medium for which the angle of refraction is 90°.
Using Snell's law as :

Here, 

Where
n₂ = Refractive index of air = 1
n₁ = refractive index of liquid
So,


n₁ = 1.269
or n₁ = 1.27
Hence, the refractive index of liquid is 1.27
Answer:
λ
=8.57 μ m
Explanation:
Given that
Ey = 375 cos [kx − (2.20 × 10¹⁴ rad/s)t] N/C
Standard form
Ey=Eo cos[k x-ωt] N/C
By comparing the given equation with the standard wave equation
Eo = 375 N/C
ω = 2.20 × 10¹⁴ rad/s
We know that ω = 2 π f
f=3.50×10¹³ Hz
We know that the velocity given as
V = f λ
λ
=Wavelength
V=Speed = 3 x 10⁸ m/s
λ
=0.00000857 m ( 1 μ m = 10⁶ m)
λ
=8.57 μ m
Answer:
<h2>Potential difference across capacitors in parallel
</h2>
Two or more capacitors are said to be connected in parallel if each one of them is connected across the same two points. In a parallel combination of capacitors potential difference across each capacitor is same but each capacitor will store different charge.