Given data
ball throws upwards at an angle 60°
Horizontal component (Vh) = 12.5 m/s,
Vertical component (Vv) = 21.7 m/s ,
The magnitude of throw/resultant velocity (V) = ?
The resultant velocity /the velocity with which ball is throws is determined by the following equation
V = √[(Vh)² + (Vv)²]
= √[(12.5)² + (21.7)²]
= 25.04 m/s
<em> The resultant velocity or the velocity with which the ball is thrown is 25 m/s</em>
The force of the electron decreases as it moves farther away because the force increases as an electron moves closer to the nucleas
If the airplane covered 790 kilometers along the ground every hour,
and if it could keep that up, and if there was no wind, and if the
airplane pointed its nose directly toward its destination and never
zigged or zagged even the slightest bit, then it would cover
790 kilometers of the distance during the first hour, another
790 kilometers of the distance during the second hour, another
790 kilometers of the distance during the third hour, 790 more
kilometers of the distance during the fourth hour, and so forth
and so on until it had arrived at its destination.
The minimum time it would need for the total trip would be
(4,700 kilometers) / (790 kilometers per hour) =
5.9494... hours (rounded)
5hours 56m 57.7seconds (rounded) .
(790 kilometers) x (1 mile / 1.609344 kilometers) = 490.88 miles (rounded)
Answer:
Zero.
Explanation:
In the general projectile motion there is only one component of acceleration which is in the vertical direction.There is no any acceleration in the horizontal direction.As we know that horizontal component of the velocity is remains constant in the projectile motion.
Therefore we cans say that in the projectile motion ,the acceleration in the horizontal direction is zero.
Therefore the answer will be zero.
