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Elanso [62]
4 years ago
11

A man can row at 6kmhr in still water and want to cross a river to a position exactly opposite his starting point. If the river

is 5km wide and his flowing at 4kmhr eastward. Find by scale drawing or other wise direction in which he must set off in order to accomplish his objective. How long will it take to cross the river
Physics
1 answer:
Lina20 [59]4 years ago
3 0

Answer:

if the river is 5km wide and is flowing at 4km/hr. eastwards find by scale ... Find either by scale drawing or by calculation (1) the direction in which he must ... He could row his boat directly across the river to point C and then run to B, or he ... A man who can swim at 5km/h in still water swims towards the east to cross arriver.

Explanation:

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An airplane is seller rates down a runway at 3.10 M/S squared 441.5 seconds from rest until finally left off the ground ,what is
sineoko [7]

Answer:

302129m

Explanation:

Using s= ut + 1/2at²

But u= 0

So

S= 1/2(3.1)(441.5)²

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6 0
4 years ago
If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge thr
Agata [3.3K]

Answer:

Resistance in the flash tube, R=3.97\times 10^{-3}\ \Omega

Explanation:

It is given that,

Speed of the bullet, v = 500 m/s

Distance between one RC constant, d = 1 mm = 0.001 m

Capacitance, C=503\ \mu F=503\times 10^{-6}\ F

The time constant of RC circuit is given by :

\tau=RC

R is the resistance in the flash tube

R=\dfrac{\tau}{C}..........(1)

Speed of the bullet is given by total distance divided by total time taken as :

v=\dfrac{d}{\tau}

\tau=\dfrac{d}{v}

\tau=\dfrac{0.001}{500}

\tau=0.000002\ s

Equation (1) becomes :

R=\dfrac{0.000002}{503\times 10^{-6}}

R=3.97\times 10^{-3}\ \Omega

So, the resistance in the flash tube is 3.97\times 10^{-3}\ \Omega. Hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
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