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lisabon 2012 [21]
3 years ago
12

A force of 500 N acts horizontally on a 10,000 g body. What is its horizontal acceleration

Physics
1 answer:
Paladinen [302]3 years ago
8 0
200n because it's 2×5=10so maybe try solving the problem like that ok does that help
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An object in space is initially stationary relative to the Earth. Then, a force begins acting on the object, starting with a for
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Answer:

21741 s i believe

Explanation:

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a wave in the ocean has an amplitude of 3m. Winds pick up suddenly, increasing the wave's amplitude to 6m. How does this change
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Answer

Hi,

An increase in amplitude from 3m to 6 m increases the energy it transports. The frequency of the wave is not affected

Explanation

Amplitude is the height of a wave where as frequency is the number of waves that pass by each second. A wave with bigger amplitude has more energy than a wave with smaller amplitude. A point where more waves pass contains more energy that is transferred every second. The change in the amplitude of a wave does not change its frequency. However, frequency is inversely related to the wavelength of a wave.

Best Wishes!

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3 years ago
If i am changing velocity, i must also have _______ and a net _________
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if i am changing velocity, i must also have <u>acceleration</u> and a net <u>force</u>

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  • Newton's first law of motion states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

According to Newton's first law of motion, without a force acting on an object, its velocity does not change. The net force acts on an object to change its velocity and cause acceleration.

Read more about velocity:

brainly.com/question/4931057

6 0
3 years ago
Ben hit a 0.25kg nail into a wood with a 5.2kg hammer. If the hammer moves witht the speed of 52 m/s and two fifth of its kineti
Art [367]

Answer:

Explanation:

Mass of nails is 0.25kg

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Then, Ben kinetic energy is given as

K.E= ½mv²

K.E= ½×5.2×52²

K.E= 7030.4J

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Internal energy (I.E) = 2/5 × K.E

Internal energy (I.E) = 2/5 × 7030.4

I.E=2812.16J.

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∆Et= K.E-I.E

∆Et= 7030.4 - 2812.16

∆Et= 4218.24J

7 0
3 years ago
A sample of water with a mass of 1 gram freezes at 32°F. At what temperature will a 100-gram sample of water freeze?
valkas [14]

Answer:

3200°F

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just add two zero's to the end

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