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lisabon 2012 [21]
4 years ago
12

A force of 500 N acts horizontally on a 10,000 g body. What is its horizontal acceleration

Physics
1 answer:
Paladinen [302]4 years ago
8 0
200n because it's 2×5=10so maybe try solving the problem like that ok does that help
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27. Calculate the impulse when an average<br> force of 10 N acts on a cart for 5.0 s.
wlad13 [49]

Answer:

50 Ns

Explanation:

Impulse = force × time

J = F Δt

J = (10 N) (5.0 s)

J = 50 Ns

6 0
4 years ago
A brick falls from a wall to the ground 3.42 m below. How much time will it take to
ddd [48]

Answer:

The time taken by the brick to hit the ground, t = 0.84 s

Explanation:

Given that,

A brick falls from a height, h = 3.42 m

The initial velocity of the brick is zero.

Since the brick is under free-falling. The time equation of a free-falling body when the displacement is given is

                                     t = \sqrt{2h/g}

where,

                                 h - height from surface in meters

                                 g - acceleration due to gravity

on substituting the values in the above equation,

                                 t =  \sqrt{2X3.14/9.8}

                                   = 0.84 s

Hence, time taken by the brick to hit the ground is t = 0.84 s

6 0
3 years ago
How much heat is lost by 2.0 grams of water if the temperature drops from 31 °C to 29 °C? The specific heat of water is 4.184 J/
Elanso [62]

Given :

Mass of water, m = 2 grams.

The temperature of water drops from 31 °C to 29 °C .

The specific heat of water is 4.184 J/(g • °C).

To Find :

Amount of heat lost in this process.

Solution :

We know, heat lost is given by :

Heat\ lost,H = ms( T_f - T_i)\\\\H = 2\times 4.184 \times ( 31 - 29 )\ J\\\\H = 16.736\ J

Therefore, amount of heat lost in this process is 16.736 J.

4 0
3 years ago
The average distance between collisions for atoms in a real gas is known as the mean free path (see pp. 298-9 in McKay). Which o
dusya [7]

Answer:

300 nm

Explanation:

R = Gas constant = 8.314 J/molK

r = Atomic radii = 1\times 10^{-10}\ m

d = Atomic diameter = 2r=2\times 10^{-10}\ m

At STP

T = Temperature = 273.15 K

P = Pressure = 100 kPa

N_A = Avogadro's number = 6.022\times 10^{23}

The mean free path is given by

\lambda=\frac{RT}{\sqrt2d^2N_AP}\\\Rightarrow \lambda=\frac{8.314\times 273.15}{\sqrt2 \pi \times (2\times 10^{-10})^2\times 6.022\times 10^{23}\times 100000}\\\Rightarrow \lambda=2.12165\times 10^{-7}\ m=212.165\times 10^{-9}\ m=212.165\ nm

The answer that best represents the mean free path for gas molecules is 300 nm

4 0
4 years ago
Dormancy helps plants survive freezing temperatures and lack of..
quester [9]
I’m not 100% but I was thinking A
6 0
3 years ago
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