Answer:
g_x = 3.0 m / s^2
Explanation:
Given:
- Change in length of spring [email protected] = 22.6 cm
- Time taken for 11 oscillations t = 19.0 s
Find:
- The value of gravitational free fall g_x at plant X:
Solution:
- We will assume a simple harmonic motion of the mass for which Time is:
T = 2*pi*sqrt(k / m ) ...... 1
- Sum of forces in vertical direction @equilibrium is zero:
F_net = k*x - m*g_x = 0
(k / m) = (g_x / x) .... 2
- substitute Eq 2 into Eq 1:
2*pi / T = sqrt ( g_x / x )
g_x = (2*pi / T )^2 * x
- Evaluate g_x:
g_x = (2*pi / (19 / 11) )^2 * 0.226
g_x = 3.0 m / s^2
2a for example the first one,2sec. You know that every second it moves 3metres further. So 2x3=6 but you start at 0.50m so 6+0.50=6.5
Cardio respiratory endurance, muscular strength, muscular endurance
The vertical component is = vsinx m/s
If you know the angle, substitute the value of x.
If you know the velocity at which it is moving, substitute it for v
Hope it helps :)
Answer;
=84 kwh
Explanation;
Electrical energy = 1000 watts
1000 watt = 1 kilo watt
1 week = 7 days
Number of hours = 7 × 12× = 84 hours
Consumption
= 1 kw × 84 hours
= 84 kwh
