Answer:
0.08735 kgm²
Explanation:
m = Mass of lower leg = 5 kg
L = Length of leg = 18 cm
g = Acceleration due to gravity = 9.81 m/s²
f = Frequency = 1.6 Hz
I = Moment of inertia
Time period is given by

Also

So,

The moment of inertia of the lower leg is 0.08735 kgm²
Answer:
pressure of the water = 3.3 ×
pa
Explanation:
given data
velocity v1 = 1.5 m/s
pressure P = 400,000 Pa
inside radius r1 = 1.00 cm
pipe radius r2 = 0.5 cm
h1 = 0 (datum at inlet)
h2 = 5.0 m (datum at inlet)
density of water ρ = 1000 kg/m³
to find out
pressure of the water
solution
we consider here flow speed in bathroom that is = v2 and Pressure in bathroom is = P2
here we will use both continuity and Bernoulli equations
because here we have more than one unknown so that
v1 × A1 = v2 × A2 × P1 + ρ g h1 + (0.5)ρ v1² = P2 + ρ g h2 + (0.5) ρ v2²
now we use here first continuity equation for get v2
v2 =
v2 =
v2 = 6 m/s
and now we use here bernoulli eqution for find here p2 that is
P2 = P1 - 0.5× ρ ×(v2² - v1²) - ρ g (h2- h1 )
P2 = 400000 - 0.5× 1000 ×(6² - 1.5²) - 1000 × 9.81 × (5-0 )
P2 = 3.3 ×
pa
Answer:
v = 282.84 m / s
Explanation:
The speed of a wave in a wire is given by the equation
.v = √ T /ρ
Where v is the speed of the wave, T the tension in the wire and ρ the density of the wire
If the tension is doubled
T = 2T₀
v = √ (2T₀ / ρ)
v = √2 √ T₀ / ρ
v = √2 v₀
calculate
v = √2 200
v = 282.84 m / s
Answer:
0.036J
Explanation:
Given parameters:
Spring constant , K = 92N/m
Compression = 2.8cm = 0.028m
Unknown:
Potential energy = ?
Solution:
To solve this problem;
P.E =
K e²
K is the spring constant
e is the compression
so;
P.E =
x 92 x 0.028² = 0.036J
Answer:
1)
from the positive x-axis.
2) 
Explanation:
Given:
speed of rowing in still water, 
1)
speed of water stream, 
we know that the direction of resultant of the two vectors is given by:

where:
the angle of resultant vector from the positive x-axis.
angle between the given vectors
When the rower wants to reach at the opposite end then:

so,




from the positive x-axis.
2)
Now the resultant velocity of rowing in the stream:



Therefore time taken to cross a 4 miles wide river:


