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tino4ka555 [31]
4 years ago
3

a cat plays with a toy mouse suspended from a light string of length 1.25 m, rapidly battling the mouse so that it acquires a sp

eed of 2.75 m/s while the string is still vertical. use energy conservation to find the mouse's maximum height above its original position
Physics
1 answer:
Liula [17]4 years ago
4 0

As per the energy conversation:

Kinetic Energy = Potential Energy

1/2 x m x v^2 = m x g x h

h = 0.5 x v^2/g

= 0.5 x (2.75 m/s) /9.81 m/s^2

= 0.385 m


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While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

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3 years ago
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4 years ago
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Charge: A piece of plastic has a net charge of +2.00 μC. How many more protons than electrons does this piece of plastic have? (
snow_lady [41]

Answer

given,

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we know,

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1 micro coulomb  charge =  6.28 x 10¹⁸ x 10⁻⁶ electron

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2.00 μC = 2 x 6.28 x 10¹² electrons

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since net charge is positive.

The number of protons should be 1.256 x 10¹³ more than electrons.

hence, +2.00 μC have 1.256 x 10¹³ more protons than electrons.

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3 years ago
An unstrained horizontal spring has a length of 0.31 m and a spring constant of 220 N/m. Two small charged objects are attached
Kruka [31]
The solution you should use is Hooke's law: F=-kx

It should have the same signs because they repel due to the stretch of the spring. 

a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be 
<span>F = kx 
270 N/m x 0.38 m = 102.6 N 
</span>
b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force. 



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4 years ago
An object is moving with uniform speed in a circle of radius r. Calculate the distance and displacement
dimaraw [331]

Answer and Explanation:

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displacement will be 2r (diameter)

the motion is uniform circular motion as the object is moving in a circular path with uniform motion

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