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2 years ago

What is A common source of stress?

Physics

2 answers:

nataly862011 [7]2 years ago

6 0

Answer: there are many sources of stress

Explanation:

1) life changes

2) chronic stressors

3) frustration

4)job stressors

5) when you are going through a conflict

Oksanka [162]2 years ago

5 0

Answer:

school, relashonships, etc.

Explanation:

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Practicing good human relations skills and having a positive attitude will

skad [1K]

Have a positive effect on you as a human being. Your attitude will improve, your charisma will spread, and you will a better, more well rounded person.

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3 years ago

Read 2 more answers

A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy. The energy used to do work

nika2105 [10]

Answer:

480J

Explanation:

Using the formula:

Delta U = Q - W

Q:Heat (J)

Delta U: Changes in internal Energy (J)

W:Work (J)

We can plug in the give numbers, Q and W.

Delta U = 658J - 178J = 480J

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2 years ago

A sealed container holding 0.0255 L of an ideal gas at 0.981 atm and 65 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w

user100 [1]

Answer:

0.911 atm

Explanation:

In this problem, there is no change in volume of the gas, since the container is sealed.

Therefore, we can apply Gay-Lussac's law, which states that:

"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"

Mathematically:

$p\propto T$

where

p is the gas pressure

T is the absolute temperature

For a gas undergoing a transformation, the law can be rewritten as:

$\frac{p_1}{T_1}=\frac{p_2}{T_2}$

where in this problem:

$p_1=0.981 atm$ is the initial pressure of the gas

$T_1=65^{\circ}+273=338 K$ is the initial absolute temperature of the gas

$T_2=41^{\circ}+273=314 K$ is the final temperature of the gas

Solving for p2, we find the final pressure of the gas:

$p_2=\frac{p_1 T_2}{T_1}=\frac{(0.981)(314)}{338}=0.911 atm$

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3 years ago

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that

loris [4]

Questions Diagram is attached below

Answer:

$T=2.08s$

Explanation:

From the question we are told that:

Speed of Train $V=3.0m.s$

Angle $\theta=12\textdegree$

Height of window $h_w=0.90m$

Width of window $w_w=2.0m$

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

$b=\frac{0.9}{tan12}$

$b=4.23$

Therefore

Distance from A-A

$d_a=2.0+4.23$

$d_a=6.23$

Therefore

Time Required to travel trough d is mathematically given as

$T=\frac{d_a}{v}$

$T=\frac{6.23}{3}$

$T=2.08s$

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2 years ago

Apply the impulse-momentum relation and the work-energy theorem to calculate the maximum value of t if the cake is not to end up

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2 years ago