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alexira [117]
3 years ago
11

If an earthquake wave having a wavelength of 13 km caused the ground to vibrate 10 times each minute, what is the speed of the w

ave?
1.2 km/s
2.2 km/s
220 m/s
22 m/s

If the amplitude in a sound wave is doubled, by what factor does the intensity of the wave increase?
2
1
8
4(my choice)
Physics
1 answer:
BARSIC [14]3 years ago
3 0

#1

Wavelength = 13 km

it vibrates 10 times each minute

so the frequency is defined by the number of vibrations per second

f = 10 per\: min

f = \frac{10}{60}

now the speed of wave is defined as

v = \lambda* f

v = 13* \frac{1}{6} = 2.2 km/s

<em>so here velocity of wave is 2.2 km/s</em>

#2

Intensity of wave is directly proportional to the square of its amplitude

so we can say

Intensity = k*(amplitude)^2

k = constant

so if amplitude is doubled then its intensity will be increased by its square

<em>so intensity is 4 times</em>


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Answer:

|a|=2.83\ m/s^2

\theta=75^o

Explanation:

<u>Net Force And Acceleration </u>

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

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The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

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|F_n|=\sqrt{14.64^2+54.64^2}

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The acceleration has a magnitude of

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\displaystyle |a|=\frac{56.57}{20}

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The direction of the acceleration is the same as the net force:

\displaystyle tan\theta=\frac{54.64}{14.64}

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