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Anastasy [175]
3 years ago
5

The concentration from analysis question 5 represents the concentration in the 10.00 mL sample that was prepared in the volumetr

ic flask using an aliquot of the solution in the 100.00 mL volumetric flask. Calculate the concentration of acetylsalicylic acid in the 100.00 mL volumetric flask. This is a simple dilution – as long as you use the correct volumes
Chemistry
1 answer:
jolli1 [7]3 years ago
7 0

Answer:

0.048 M

Explanation:

Note that the Concentration from Question 5= .00096 M

To Prepere  of commercial aspirin solution, take the following steps:

  • Mix 1 aspirin tablet and 10 mL of 1 M NaOH in a 125 mL Erlenheyemer flask, heat to boil.

  • Transfer solution to 100 mL volumetric flask and fill to 100 mL mark with deonized water. Cover and mix solution thoroughly.

  • Using pipette transfer a 0.200 mL of solution to a 10 mL volumetric flask and dilute it with the 0.02 M buffered iron (III) chloride solution. Transfer it  to test tube.

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Answer:

D = m/v.

Explanation:

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3 years ago
determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

<h2 />

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

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8 0
1 year ago
SCIENCE, PLEASE HELP.
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Answer: B

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protons are positive,

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and neutrons are neutral.

the amount of electrons to protons is always the same in a balanced atom.

electrons can be removed creating "ions" which is simply an unbalanced atom. removing protons would result in a different type of atom or element.

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