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3 years ago

HEY CAN ANYONE ANSWER DIS RQ PLS!!!!!

Physics

2 answers:

____ [38]3 years ago

8 0

Answer:

Hey!

Your first answer is ALL OF THE ABOVE!

Your second answer is YES!

<h2>I HOPE THIS HELPED YOU!</h2>

zalisa [80]3 years ago

5 0

Answer: all of the above and yes

hope thsi helps

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The train departed 100 meters in 10 seconds How far has the train gone in the last 2 seconds

zzz [600]

Answer:

20 meters.

Explanation:

Since it went 100 meters in 10 seconds, that means it is going 10 meters per second. In 2 seconds, it must have gone 20 meters, if the speed is constant.

5 0

2 years ago

What effects occur when heat energy is added to a system

Kobotan [32]

It could possibly melt things

6 0

3 years ago

Review. As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking always st

anyanavicka [17]

To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,

The circumference of the planet is,

$\phi = 25.1m$

Under the mathematical value the radius would be

$\phi = 2\pi r$

$r = \frac{25}{2\pi}$

$r = 3.9788km$

Using second equation of motion

$x = \frac{1}{2} at^2$

Replacing the values given,

$1.4 = \frac{1}{2} a (29.2)^2$

Rearranging and solving for 'a' we have,

$a = 0.003283m/s^2$

Using the value of acceleration due to gravity from Newton's law we have that

$a = \frac{GM}{r^2}$

Here,

r = Radius of the planet

G = Gravitational Universal constant

M = Mass of the Planet

$\frac{(6.67*10^{-11})*M}{(3.9788*10^3)^2} = 0.003283$

$M = 7.79201*10^{14}kg$

Therefore the mass of this planet is $7.79201*10^{14}kg$

5 0

3 years ago

High altitude high velocity rivers of air are called

forsale [732]

The answer to the question would be jet streams.

3 0

2 years ago

Read 2 more answers

A boat is heading across a river at a velocity of 25 mph. The river is flowing downstream at 10 mph. What is the actual velocity

AnnyKZ [126]

Principle: Pythagorean theorem

Given:
Let a = boat velocity = 25 miles per hour
b = river velocity = 10 miles per hour

Required: c = actual velocity

Solution:

c^2 = a^2 + b^2
c^2 = (25)^2 + (10)^2
c^2 = 725
(c^2)^0.5 = (725)^0.5
c = 26.93 miles per hour

<em>ANSWER: Actual boat velocity is 26.93 miles per hour</em>

8 0

2 years ago