Answer:
How does the drink content affect an individual's blood pressure?
Explanation:
In every experiment using the scientific method, an observation lays the foundation of that experiment. A problem must be observed, which then leads to asking a SCIENTIFIC QUESTION in order to investigate. A scientific question must include the variable being changed called INDEPENDENT VARIABLE and the variable being measured called DEPENDENT VARIABLE.
In this experimental procedure or set up,
- Group 1 drinks 500 mL of coffee a day.
- Group 2 drink 500 mL of tea a day,
- Group 3 is a control group i.e no drink
At the end of 60 days all participants
blood pressure is tested.
This set up indicates that the variable being changed (independent) is the DRINK CONTENT while the variable being measured (dependent) is the BLOOD PRESSURE. Hence, these variables serve as the template to ask a scientific question which goes thus:
HOW DOES THE DRINK CONTENT AFFECT AN INDIVIDUAL'S BLOOD PRESSURE?
This scientific question relates how the independent variable (drink) causes the dependent variable to respond (blood pressure).
A. The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is centrifugal force.
<h3>What is centrifugal force?</h3>
Centrifugal force is an inertial force that appears to act on all objects when viewed in a rotating frame of reference.
This force is directed away from the center around which the body is moving.
<h3>What is centripetal force?</h3>
This is force that acts on a body moving in a circular path and is directed towards the center around which the body is moving.
While centripetal force is directed towards to the center, the centrifugal force is directed away.
Thus, the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is centrifugal force.
Learn more about centrifugal force here: brainly.com/question/20905151
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Acceleration(a) is the change in velocity(Δv) over the change in time(Δt). so just divide your velocity and time.
Answer:
Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day
Part (b) The specific discharge of the flow is 0.0363 m/day
Part (c) The average linear velocity of the flow is 0.242 m/day
Part (d) The time taken for a tracer to travel the distance between the observation wells is 4132.23 days = 99173.52 hours
Explanation:
Part (a) the flow rate per unit width of the aquifer
From Darcy's law;
where;
q is the flow rate
K is the permeability or conductivity of the aquifer = 25 m/day
b is the aquifer thickness
dh is the change in th vertical hight = 50.9m - 52.35m = -1.45 m
dl is the change in the horizontal hight = 1000 m
q = -(25*30)*(-1.45/1000)
q = 1.0875 m³/day
Part (b) the specific discharge of the flow
V = 0.0363 m/day
Part (c) the average linear velocity of the flow assuming steady unidirectional flow
Va = V/Φ
Φ is the porosity = 0.15
Va = 0.0363 / 0.15
Va = 0.242 m/day
Part (d) the time taken for a tracer to travel the distance between the observation wells
The distance between the two wells = 1000 m
average linear velocity = 0.242 m/day
Time = distance / speed
Time = (1000 m) / (0.242 m/day)
Time = 4132.23 days
Answer: 1.88
Explanation
Applying Snell’s Law, sin(1)/sin(2) = n(2)/n(1), where n is the index of refraction and sin 1 and 2 being of incidence and refracted respectively.
1) sin35/sin24 = n(2)/1.33
2) 1.41 = n(2)/1.33
3) n(2) = 1.41 x 1.33
4) n(2) = 1.88
Hope this helps :)
