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Kaylis [27]
3 years ago
9

Un isótopo de un elemento metálico tiene un número de masa de 65 y tiene 35 neutrones en su núcleo. El catión derivado de dicho

isótopo tiene 28 electrones. Identifique el elemento, y la carga correspondiente del ión.
Chemistry
1 answer:
poizon [28]3 years ago
8 0
According to Data,
                             Mass Number  =  65

                             # of Neutrons  =  35

As we know,
                             Mass Number  =  # of protons + # of Neutrons
Solving for # of protons,
                                # of protons  =  Mass Number - # of Neutrons
Putting values,
                                # of Protons  =  65 -35

                                # of protons  =  30
As, 

# of protons is the atomic number, so element with atomic number 30 is Zinc.

The cation derived from it has 28 electrons,
So, Zinc having 30 electron will be left with two extra protons, and each proton has +1 charge.

Result:
                                                    Zn
²⁺
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How many grams of copper (II) hydroxide can be prepared from 2.4 grams of copper (II) nitrate (Cu(NO3)2 ) and excess sodium hydr
andreyandreev [35.5K]

Answer:

percentage yield = 67%

Explanation:

Mass of Cu(NO₃)₂  = 15.25 g

Mass of NaOH   = 12.75 g

Percentage yield = ?

Solution:

Cu(NO₃)₂ + 2NaOH   →  Cu(OH)₂ + 2NaNO₃

Moles of Cu(NO₃)₂:

Number of moles = mass/ molar mass

Number of moles = 15.25 g /187.56 g/mol

Number of moles = 0.08 mol

Moles of NaOH :

Number of moles = mass/ molar mass

Number of moles = 12.75 g / 40 g/mol

Number of moles = 0.32 mol

Now we will compare the moles of Cu(OH)₂ with NaOH and Cu(NO₃)₂.      NaOH             :      Cu(OH)₂

                               2                   :          1

                               0.32              :           1/2×0.32 = 0.16 mol

                            Cu(NO₃)₂         :           Cu(OH)₂

                                  1                  :               1

                             0.08                :              0.08

The number of moles produced by  Cu(NO₃)₂  are less so it will limiting reactant.

Mass of Cu(OH)₂:

Mass = number of moles × molar mass

Mass = 0.08 mol × 97.6 g/mol

Mass = 7.808 g

Theoretical yield = 7.808 g

Percent yield:

percentage yield = Actual yield/ theoretical yield ×  100

percentage yield = 5.23 g/  7.808 g ×  100

percentage yield = 0.67 ×  100

percentage yield = 67%

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density=mass/volume

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d=100/20

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