Moles KClO₃ = 0.239
<h3>Further explanation</h3>
Given
Reaction
2KClO₃(s) ⇒2KCl(s) + 3O₂(g)
P water = 23.8 mmHg
P tot = 758 mmHg
V = 9.07 L
T = 25 + 273 = 298 K
Required
moles of KClO₃
Solution
P tot = P O₂ + P water
P O₂ = P tot - P water
P O₂ = 758 - 23.8
P O₂ = 734.2 mmHg = 0.966 atm
moles O₂ :
n = PV/RT
n = 0.966 x 9.07 / 0.082 x 298
n = 0.358
From equation, mol ratio KClO₃ : O₂ = 2 : 3, so mol KClO₃ :
= 2/3 x mol O₂
= 2/3 x 0.358
= 0.239
Answer:
A. H₃O⁺ + CN⁻ → H₂O + HCN
B. OH⁻ + NH₄⁺ → NH₃ + H₂O
C. CN⁻ + NH₄⁺ → HCN + NH₃
D. HSO₄⁻ + CH₃COO⁻ → SO₄²⁻ + CH₃COOH
E. ClO⁻ + NH₃ → NO REACTION
Explanation:
Part A.
Sodium cyanide consist of Na⁺ and CN⁻ ions. CN⁻ is a conjugate base and accept H⁺ ion from nitric acid to form HCN (hydrogen cyanide).
Part B.
Ammonium chloride consist of NH₄⁺ and Cl⁻ ions. Sodium hydroxide is a strong base dissociate completely in solution convert into ammonium hydroxide and sodium chloride.
Part C.
Sodium cyanide consist of counter ion Na⁺ . CN⁻ combined with ammonium bromide to form ammonium cyanide and sodium bromide.
Part D.
Potassium hydrohen sulphate consist of potassium counter and hydrogen sulphate ion. Hydrogen sulphate combined with acetate ion to form acetic acid and sulphate ion.
Part E.
There have no reaction because hypochlorite and ammonia both are bases.
Answer:
The average atomic mass is 86.565
Explanation:
An element's average atomic mass is the sum of the products of the masses of the isotopes of the element and their percentage abundance divided by 100
The average atomic mass of the Element X is given as follows;
Isotope type 1 (85.91) ×
Isotope 
Abundance (%) Mass /100 Portion of average mass
Type 1 67.25 × 85.91 ÷ 100 57.774475
Type 2 32.75 × 87.91 ÷ 100 28.790525
Average atomic mass = 86.565
The average atomic mass = 86.565.
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