All categories

3 years ago

I need some help with this problem.

Physics

1 answer:

dalvyx [7]3 years ago

3 0

This picture is a graph. Do you see the marks over on the left side ?
It says "Brightness". The Low brightness is on the bottom, and the
High brightness is on the top. This shows you that the brightest stars
are the highest ones on the graph.

Now look on the graph. Down near the bottom are Proxima Centauri and
the white dwarfs. Also, our Sun is not too far up. Way up near the top, you
see Supergiants. "Betelgeuse" is on the right side, and "Spica" is on the
left side. Those are the brightest ones on the graph.

The choices in your question are cut off below the bottom of thepicture. But
this much discussion should be enough to help you choose the best answer.

You might be interested in

Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter

Bas_tet [7]

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

6 0

3 years ago

1. A 4-N force is used to move an object 2 m in 10 s. Which of the following is the power generated while moving the object?

guajiro [1.7K]

Power is the work done per unit time. Therefore,

$\begin{gathered} p=\frac{w}{t} \\ \text{where} \\ w=\text{work done} \\ t=\text{time} \end{gathered}$

Therefore,

$\begin{gathered} \text{work done=fd} \\ f=force=4N \\ d=\text{displacement}=2m \\ t=2\sec s \\ p=\frac{fd}{t}=\frac{4\times2}{10}=\frac{8}{10}=0.8watts \end{gathered}$

4 0

1 year ago

HELLO , PLZ HELP .

sergey [27]

Answer:

the pressure due to the water on the diver is 200,000 pascal

pressure = height × density × acceleration due to gravity

p = 20×1000×10

p=200,000 pascal

6 0

3 years ago

A tiger runs at 58 km/h [S]. What is the displacement of the tiger in 38 s?

Artyom0805 [142]

58 K/h = 58000/3600= 16.1 m/s
In 38 s displacement is 38x16.1= 612.2 m

3 0

3 years ago

Is it possible for the momentum of a system consisting of two carts on a low-friction track to be zero even if both carts are mo

choli [55]

Answer:

Yes, if the two carts are moving into opposite directions

Explanation:

The total momentum of the system of two carts is given by:

$p=m_1 v_1 + m_2 v_2$

where

m1, m2 are the masses of the two carts

v1, v2 are the velocities of the two carts

Let's remind that v (the velocity) is a vector, so its sign depends on the direction in which the cart is moving.

We want to know if it is possible that the total momentum of the system can be zero, so it must be:

$p=0\\m_1 v_1 + m_2 v_2 = 0\\m_1 v_1 = -m_2 v_2$

From this equation, we see that this condition can only occur if v1 and v2 have opposite signs. Opposite signs mean opposite directions: therefore, the total momentum can be zero if the two carts are moving into opposite directions.

4 0

3 years ago