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lions [1.4K]
3 years ago
6

The change in internal energy during one complete cycle of a heat engine A. equals the net heat flow into the engine. B. equals

zero. C. equals the heat energy exhausted from the engine. D. equals the heat energy entering the engine.
Physics
1 answer:
Stels [109]3 years ago
7 0

Answer:

B. equals zero

Explanation:

Given data

one complete cycle = heat flow

solution

we have given that when heat engine complete 1 cycle change in energy = net heat flow

that is always equal to zero

from first law of thermodynamics that

ΔU = Q + W

we know ΔU is the change internal energy in system and Q is net heat transfer in system and W is  net work done in system

therefore change of internal energy during one cycle

ΔU = Ufinal -  Uinitial

ΔU  = Uinitial  -  Uinitial  = 0

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Describe what would happen if you rubbed a mineral with a Mohs hardness value of 7 against a mineral with a value of 5?
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Hoped this helped!
6 0
3 years ago
While moving a box 10.0 m across the floor, Sam pushes with a force of 150 N to the right. The force friction acting on the box
svet-max [94.6K]

Answer:

Explanation:required formula is

W 1=F*S

W1=work done by Sam =?

F=force applied by sam=150N

S=displacement =10m

again

W2=F*S

W2=work done by friction =?

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please feel free to ask if you have any questions

4 0
3 years ago
Find the ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance betw
Snezhnost [94]

Answer:

The ratio of the new force over the original force is 16

Explanation:

Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

F_G=G\,\frac{M_1\,\,M_2}{D^2}

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G

which is 16 times the original force.

So the ratio of the new force over the original force is 16

5 0
3 years ago
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