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Rina8888 [55]
2 years ago
5

Alpha particles are emitted during the radioactive decay of

Physics
1 answer:
photoshop1234 [79]2 years ago
7 0

Answer:

Uranium 238  

Uranium 238  → thorium-234 + α particle (He²⁺ helium nucleus)

Explanation:

A uranium-238 nucleus, which is termed the parent nucleus, experiences radioactive decay with the emission of an alpha particle to form thorium-234, which is known as the daughter nuclide by the emission of an alpha particle which is made up of to neutrons and two protons.

When nucleus of a radioactive atom decays by emitting an alpha particle, which is equivalent to a helium nucleus, to transform into a different atomic nucleus with a lesser mass (less by four)  and a reduced atomic number (reduced by two), it is said to have undergone an alpha decay or α-decay.

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On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters
dimulka [17.4K]

Answer:

d_1 = 16 d

Explanation:

As we know that initial speed of the fall of the stone is ZERO

v_i = 0

also the acceleration due to gravity on Mars is g

so we have

d = v_i t + \frac{1}{2}gt^2

now we have

d = 0 + \frac{1}{2}g t^2

now if the same is dropped for 4t seconds of time

then again we will use above equation

d_1 = 0 + \frac{1}{2}g(4t)^2

d_1 = 16(\frac{1}{2}gt^2)

d_1 = 16 d

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3 years ago
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What is the greatest cause for concern regarding hydroelectric power?
nexus9112 [7]

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destroys habitats is the main one

Explanation:

eye sore can be one and it can burst causing a flood is also one :)

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A ball is thrown horizontally from a 19 m -high building with a speed of 2.0 m/s . How far from the base of the building does th
bazaltina [42]
Using the formula: ΔY = V₀y * t + (1/2) * ay * t²

Solve for time and get: 1.968s

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3 years ago
What does a worm and wheel mechanism do to torque and speed​
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Answer:Explanation:

Image result for what does a worm and wheel mechanism do to torque and speed​

Like other gear arrangements, a worm drive can reduce rotational speed or transmit higher torque. ... Each full 360 degree turn of a single start worm advances the gear by one tooth. For a multi start worm the gear reduction equals the number of teeth on the gear divided by the number of starts on the worm.

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3 years ago
Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force
gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

F=k\frac{q_1q_2}{r^2}

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(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}

F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N

Ft=0N

Hope this helps!!

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