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Rina8888 [55]
3 years ago
5

Alpha particles are emitted during the radioactive decay of

Physics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

Uranium 238  

Uranium 238  → thorium-234 + α particle (He²⁺ helium nucleus)

Explanation:

A uranium-238 nucleus, which is termed the parent nucleus, experiences radioactive decay with the emission of an alpha particle to form thorium-234, which is known as the daughter nuclide by the emission of an alpha particle which is made up of to neutrons and two protons.

When nucleus of a radioactive atom decays by emitting an alpha particle, which is equivalent to a helium nucleus, to transform into a different atomic nucleus with a lesser mass (less by four)  and a reduced atomic number (reduced by two), it is said to have undergone an alpha decay or α-decay.

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a 4kg sample of water absorbs 500 joules of energy.How much did the water temp change.The specific heat of water is 4200 J/(kg C
Ymorist [56]

Answer:

0.02976°C

Explanation:

Heat Supplied = mcø

ø = 500/(4*4200)

ø = 0.02976 °C

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Convective cooling cools rocks much more rapidly than heat conduction. hydrothermal circulation represents convective cooling at
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When geophysicists measure the geothermal gradient in areas on the ridges where there is no activity hydrothermally, the gradient is far below than what is predicted theoretically, but when measured near hydrothermal vents it is more than what is predicted. This is because most of the heat is being carried through convection by hydrothermal systems so that the average gradient when measured far from the circulation would be depressed or lower.
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3 years ago
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Umnica [9.8K]
B is the correct answer according to my calculations.
5 0
3 years ago
Read 2 more answers
At the beach in San Francisco (0 meters) the pressure of the atmosphere is 101.325 kPa
Korvikt [17]

Answer:

P = -\frac{17978}{1609344}(h)+101.325

Explanation:

Given

h = height

P = Pressure

(h_1,P_1) = (0,101.325)

(h_2,P_2) = (1609.344 ,83.437 )

Required

Determine the linear equation for P in terms of h

First, we calculate the slope/rate (m);

The following formula is used:

m = \frac{P_2 - P_1}{h_2 - h_1}

Substitute values for P's and h's

m = \frac{83.347 - 101.325}{1609.344- 0}

m = \frac{-17.978}{1609.344}

m = -\frac{17.978}{1609.344}

Multiply by 1000/1000

m = -\frac{17.978 * 1000}{1609.344*1000}

m = -\frac{17978}{1609344}

The equation is then calculated using:

P - P_1 = m(h - h_1)

Substitute values for m, h1 and P1

P - P_1 = m(h - h_1)

P - 101.325 = -\frac{17978}{1609344}(h - 0)

P - 101.325 = -\frac{17978}{1609344}(h)

Make P the subject

P = -\frac{17978}{1609344}(h)+101.325

<em>The above is the required linear equation</em>

8 0
3 years ago
A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
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