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Rina8888 [55]
3 years ago
5

Alpha particles are emitted during the radioactive decay of

Physics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

Uranium 238  

Uranium 238  → thorium-234 + α particle (He²⁺ helium nucleus)

Explanation:

A uranium-238 nucleus, which is termed the parent nucleus, experiences radioactive decay with the emission of an alpha particle to form thorium-234, which is known as the daughter nuclide by the emission of an alpha particle which is made up of to neutrons and two protons.

When nucleus of a radioactive atom decays by emitting an alpha particle, which is equivalent to a helium nucleus, to transform into a different atomic nucleus with a lesser mass (less by four)  and a reduced atomic number (reduced by two), it is said to have undergone an alpha decay or α-decay.

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Explain Rutherford's experiment?
Ipatiy [6.2K]

Answer:

Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.

Explanation:

Rutherford bombarded aluminum foil with beam of light known as alpha particles. The mass of this alpha particle is equivalent to helium atom.

When this alpha particles were made to strike the aluminum foil, some passed through the foil, some were reflected and speed others changed.

The ones reflected encountered heavier particle known as the nucleus, preventing them from passing through it. The whole observations indicated that atom is not is uniformly charged sphere as proposed by J.J Thomson.

Rutherford proposed new model known as the Planetary model of atom, which described atom as containing a nucleus which is revolved by electron, just like planets revolve round the sun. And this nucleus contains opposite charge to electron which is proton, to balance the motion.

7 0
3 years ago
Without using a micrometer screw gauge, how do I find the average diameter of a long piece of thin wire using a metre rule and a
Mice21 [21]

Answer:

Wind the long piece of thin wire around the uniform glass rod multiple times, find the length of the total diameters using the metre ruler, and divide by the number of times you wound it around the rod.

Explanation:

Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.

For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.

5 0
2 years ago
Drew wants to convert square mils to circular mils in an area calculation. How does he do this?
bija089 [108]

Answer:

i dont know

Explanation:

blah blah blah your welcome

6 0
3 years ago
A car moving with an initial speed v collides with a second stationary car that is one-half as massive. After the collision the
Mashutka [201]

Answer:

4v/3

Explanation:

Assume elastic collision by the law of momentum conservation:

m_1v = m_1v_1 + m_2v_2

where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively

Substitute m_2 = m_1/2 \& v_1 = v/3

m_1v = \frac{m_1v}{3} + \frac{m_1v_2}{2}

Divide both side by m_1, then multiply by 6 we have

6v = 2v + 3v_2

3v_2 = 4v

v_2 = \frac{4v}{3}

So the final speed of the second car is 4/3 of the first car original speed

5 0
3 years ago
Name one reason why you should pour milk in before cereal.
krok68 [10]

Answer:

splashing

Explanation:

if you put in the cereal after the milk it will splash everywhere, causing a waste of milk, and a loss of time.

5 0
3 years ago
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