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nydimaria [60]
3 years ago
15

Which of the following statements is true regarding a covalent bond in CO?. .A. Valence electrons are transferred to the oxygen

atom.. . B.The bond length is less than the sum of the two atomic radii.. . C.Bonding electrons are stationary in the CO molecule.. . D.all of the above. . E.none of the above.
Chemistry
1 answer:
Sonbull [250]3 years ago
8 0
The statements that are actually correct among the given options are:
<span>Valence electrons are transferred to the oxygen atom.
</span>The bond length <span>is less than the sum of the two atomic radii.
</span><span>Bonding electrons are stationary in the CO molecule
</span>So the correct option among all the options that are given in the question is the fourth option or option "D".
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Butanal, an aldehyde, can be made from 1-bromobutane, but it requires two reactions in sequence. What are the two reagents that
hammer [34]

Answer:

See explanation and image attached

Explanation:

My aim is to convert 1-bromobutane to butanal. The first step is to react the 1-bromobutane substrate with water. This reaction occurs by SN2 mechanism to yield 1-butanol. Hence reagent A is water.

1-butanol is now reacted with an oxidizing agent such as acidified K2Cr2O7 (reagent B) to yield butanal. Note that primary alkanols are oxidized to alkanals.

These sequence of reactions are shown in the image attached.

4 0
3 years ago
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
3 years ago
Calculate density of aluminum if 27.6cm^3 has a mass of 74.6g
rjkz [21]
First , 27.6 cm^3 is equal to 27.6 ml

Density = mass g / volume cm^3

= 74.6 / 27.6 = ........ g/cm^3
6 0
3 years ago
Read 2 more answers
student has calibrated his/her calorimeter and finds the heat capacity to be 14.2 J/°C. S/he then determines the molar heat capa
nika2105 [10]

Answer:

24.03 J/mol.ºC

Explanation:

For a calorimeter, the heat lost must be equal to the heat gained from water plus the heat gained from calorimeter, which has the same initial temperature as the water.

-Qal = Qw + Qc (minus signal represents that the heat is lost)

-mal*Cal*ΔTal = mw*Cw*ΔTw + Cc*ΔTc

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-25.5*Cal*(22.7 - 100) = 99.0*4.186*(22.7 - 18.6) + 14.2*(22.7 - 18.6)

1971.15Cal = 1699.10 + 58.22

1971.15Cal = 1757.32

Cal = 0.89 J/g.ºC

The molar mass of Al is 27 g/mol

Cal = 0.89 J/g.ºC * 27 g/mol

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6 0
3 years ago
True or false <br> If an atom is charged positive, it contains more protons than electrons.
tia_tia [17]

Answer:

TRUE

Explanation: because it is positively charged and protons are positive ions

7 0
3 years ago
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