The range of electromagnetic waves placed in a certain order is called the___________

What is the energy of a baby who weighs 20 N sitting on a 1.5 m high chair

guajiro [1.7K]

The energy of the baby is gravitational potential energy, and it is equal to the weight of the baby times its height from the ground:
$U=(mg) h$
where
mg=20 N is the weight (the mass times the gravitational acceleration)
h=1.5 m is the height from the ground
If we plug the numbers into the equation, we find
$U=(mg)h=(20 N)(1.5 m)=30 J$

3 0

4 years ago

How are sunspots related to prominences and solar flares?

solniwko [45]

<h2><u> Answer:</u></h2><h2><u /></h2>

The Sun is a star that experiences changes in its activity in a cycle of about 11 years, known as the solar cycle. During that time, the amount of sunspots on its surface may vary.

But first it is necessary to define what a sunspot is.

A <u>sunspot </u>is a region of the Sun that has a lower temperature than its surroundings, and with an intense magnetic activity. It consists of a dark central region, called <em>"umbra"</em>, surrounded by a lighter region<em>"penumbra"</em>.

Now, a solar protuberance or <u>prominence</u> is a large gaseous structure located on the surface of the Sun, often in a loop shape, which emerges from the surface of the Sun, the photosphere, and extends to reach the solar Corona. It is caused by disturbances in the Sun's magnetic field (hence it is<u> related to sunspots</u>) and, although most of the gas expelled returns to the surface, sometimes this can release particles that can reach the Earth.

In this context, a <u>solar flare</u> is a sudden, rapid and intense variation of brightness that is observed on the surface of the Sun due to an explosion of hot gases. It releases a large amount of energy in the form of electromagnetic radiation, energetic particles and mass in motion. These phenomena take place in active regions of the Sun, areas of strong magnetic field, and especially in sunspots with great magnetic complexity.

These eruptions are also known as Coronal Mass Ejections (CME), since they occur in the Sun's Corona layer; and can produce X-rays and gamma rays. However, <u>they are classified according to the peak of X-ray flow</u> by the letters A, B, C, M or X, where each letter (or class) represents an increase in energy production 10 times greater than the previous one.

In summary:

<h2> When a sunspot is observed it is because in that region there was a coronal mass ejection, also known as a solar flare. This in turn is related to solar prominences. </h2>

7 0

3 years ago

Pls help ASAP

12345 [234]

Answer:

a. 4.733 × 10⁻¹⁹ J = 2.954 eV b i. yes ii. 0.054 eV = 8.651 × 10⁻²¹ J

Explanation:

a. Find the energy of the incident photon.

The energy of the incident photon E = hc/λ where h = Planck's constant = 6.626 × 10⁻³⁴ Js, c = speed of light = 3 × 10⁸ m/s and λ = wavelength of light = 420 nm = 420 × 10⁻⁹ m

Substituting the values of the variables into the equation, we have

E = hc/λ

= 6.626 × 10⁻³⁴ Js × 3 × 10⁸ m/s ÷ 420 × 10⁻⁹ m

= 19.878 × 10⁻²⁶ Jm ÷ 420 × 10⁻⁹ m

= 0.04733 × 10⁻¹⁷ J

= 4.733 × 10⁻¹⁹ J

Since 1 eV = 1.602 × 10⁻¹⁹ J,

4.733 × 10⁻¹⁹ J = 4.733 × 10⁻¹⁹ J × 1 eV/1.602 × 10⁻¹⁹ J = 2.954 eV

b. i. Is this energy enough for an electron to leave the atom

Since E = 2.954 eV is greater than the work function Ф = 2.9 eV, an electron would leave the atom. So, the answer is yes.

ii. What is its maximum energy?

The maximum energy E' = E - Ф = 2.954 - 2.9

= 0.054 eV

= 0.054 × 1 eV

= 0.054 × 1.602 × 10⁻¹⁹ J

= 0.08651 × 10⁻¹⁹ J

= 8.651 × 10⁻²¹ J

7 0

3 years ago

n a ballistics test, a potato gun shoots a 0.34 kg potato into a 5.0 kg catching cart. The cart recoils at 3.7 m/s after catchin

Gala2k [10]

The initial velocity of the potato is 54.41 m/s.

The given parameters:

<em>Mass of the potato, m = 0.34 kg</em>
<em>Mass of the cart, m = 5.0 kg </em>
<em>Velocity of the recoil, u₂ = 3.7 m/s</em>

<em />

The initial velocity of the potato is calculated by applying the principle of conservation of energy as follows;

$m_1u_1 = m_2 u_2\\\\u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{5 \times 3.7}{0.34} \\\\u_1 = 54.41 \ m/s$

Thus, the initial velocity of the potato is 54.41 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0

3 years ago

A car moving with an initial speed of 25 m/s slows down to a speed of 5 m/s in 10 seconds Calculate a) the acceleration of the c

stealth61 [152]

Answer :

(a) The acceleration of the car is, $-2m/s^2$

(b) The distance covered by the car is, 150 m

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 5 m/s

u = initial velocity = 25 m/s

t = time = 10 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

$5m/s=25m/s+a\times (10s)$

$a=-2m/s^2$

The acceleration of the car is, $-2m/s^2$

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity = 25 m/s

t = time = 10 s

a = acceleration of the car = $-2m/s^2$

Now put all the given values in the above equation 2, we get:

$s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2$

By solving the term, we get:

$s=150m$

The distance covered by the car is, 150 m

8 0

3 years ago

The range of electromagnetic waves placed in a certain order is called the____________.