Ke= 1/2 mv ^ 2
15x 15 = 225
225 x 30 = 6750
6750/2 = 3375 J
Ke = 3375 J
Answer:4
Explanation:
Given


Mass of stick is 
Let T be the tension in the red string
Now if the red string is cut , suppose T is the tension in the blue rod immediately after cut
Therefore



Answer:15,883.63 KJ
Explanation:
Given
Power=400 W
Freezing compartment temperature is 273 K
Outside air Temperature=306 K
Time =80 minutes
Energy Required to deliver 400 w power in 80 minutes
E=1920 KJ
and we know COP of refrigerator is given by




Therefore 15,883.63 KJ is removed in 80 minutes
Answer:
Explanation:
In the calculation of distance we do not take into account the direction of movement .So only magnitude of movement is taken care of.
On the other hand , in respect of displacement , we take into account even direction of movement along with magnitude.
Distance covered by flea = 45 - 27 = 18 cm
Displacement by flea = 27 - 45 = - 18 cm
Speed = Distance covered / time
= 18 / 3 = 6 cm / s
Velocity = - 18 / 3 = - 6 cm /s.
Answer:
Explanation:
Height of building
H = 6m
Horizontal speed of first balloon
U1x = 2m/s
Second ballot is thrown straight downward at a speed of
U2y = 2m/s
Time each gallon hits the ground
Balloon 1.
Using equation of free fall
H = Uoy•t + ½gt²
Uox = 0 since the body does not have vertical component of velocity
6 = ½ × 9.8t²
6 = 4.9t²
t² = 6 / 4.9
t² = 1.224
t = √1.224
t = 1.11 seconds
For second balloon
H = Uoy•t + ½gt²
6 = 2t + ½ × 9.8t²
6 = 2t + 4.9t²
4.9t² + 2t —6 = 0
Using formula method to solve the quadratic equation
Check attachment
From the solution we see that,
t = 0.9211 and t = -1.329
We will discard the negative value of time since time can't be negative here
So the second balloon get to the ground after t ≈ 0.92 seconds
Conclusion
The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.