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lianna [129]
3 years ago
5

29.) What charge would you expect from a Group 1 atom when it becomes an ion?

Chemistry
2 answers:
Veronika [31]3 years ago
8 0

Answer:

d

Explanation:

It is 1+ because when the periodic table is drawn well into there groups become cations

gavmur [86]3 years ago
8 0
The answer here would be d
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Which of the following would not produce a sound?<br> some pls help me
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sound waves can not be carried in space

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A moist red litmus paper is used for testing ammonia gas ,why​
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when the red litmus paper is placed in a jar of ammonia, the red litmus paper turns into blue as ammonia gas is basic in nature. It confirms the alkalinity of the ammonia gas.

6 0
3 years ago
Determine the enthalpy for this reaction: Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
ivanzaharov [21]
<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol

</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
    reactants                         products

products- reactants:</span><span>

(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
<span>
</span>






6 0
3 years ago
Calculate the following:
Brrunno [24]

Follow these steps to solve the given equation:

Multiply the two decimal figures together and find the sum of the exponents, that is,

(1.5 * 1.89) * 10 ^4+3

(2.835) * 10^7

10^7 can also be written as e.70

'e' stands for exponential. 

Therefore, we have  2. 835 e 7.0 = 2.8 e 7.0.

Based on the calculations above, the correct option is A. 

4 0
3 years ago
Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. C
Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

6 0
3 years ago
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