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bogdanovich [222]
3 years ago
12

What are the costs and costs of using door mat​

Chemistry
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

$149 depending where you live.

Explanation:

You might be interested in
Identify all of the electrophilic centers in (r)-(−)-carvone below. select all that apply.
drek231 [11]
)-(−)-Carvone is responsible for the characteristic
minty odor and flavor of spearmint oil, and it can also serve as a
useful chiral starting material for organic synthesis. A
carbon-carbon π bond is normally nucleophilic, but one of the two
carbon-carbon π bonds in (R)-(−)-carvone is actually
electrophilic!



Draw resonance structures of (R)-(−)-carvone.
Do not draw resonance and curved arrows in your answer. Include
formal charges and lone pais in yo

4 0
3 years ago
You need to dissolve cacl2 in water to make a mixture that is 35% calcium chlorode by mass. if the total mass of the mixture is
nadya68 [22]
((mass solute)/(mass solution)) * 100% =35%
mass CaCl2=0.35*352.5=123.4 g CaCl2
6 0
3 years ago
Identify the true statements regarding α-1, 6 linkages in glycogen.A. The number of sites for enzymes action on a glycogen molec
kenny6666 [7]

Answer:

C. The reaction that forms α-1, 6 linkages is catalyzed by branching enzymes.

Explanation:

α-glucan branching enzyme which can also be called the Brancher enzyme or glycogen-branching enzyme is the enzyme responsible for the side chain reaction that attaches at carbon atom 6 of a glucose unit (an α-1,6-glycosidic bond).

This branching enzyme attaches a string of seven glucose units to the carbon at the C-6 position on the glucose unit, forming the α-1,6-glycosidic bond.

5 0
3 years ago
Which element had the longest effect on human history?
Dovator [93]
Oxygen I guess :)))       

6 0
3 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Inessa [10]

Answer:

The answer is "\bold{4.97 \times 10^{-2}}"

Explanation:

Please find the complete question in the attached file.

Equation:

2SO_2+O_2  \leftrightharpoons 2SO_3

at t=0 3.3   \ \ \ \ \ \ \ \ \ \ 0.79

at equilibrium 3.3-p \ \ \ \ \ \ \ \ \ \ 0.79 - \frac{P}{2} \ \ \ \ \ \ \ \ \ \ \ \ P

p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\

     =\frac{0.47^2}{2.83^2\times 0.555}\\\\=4.97 \times 10^{-2}

8 0
3 years ago
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