Two point charges are on the y axis. A 4.50-σC charge (
) is located at y=1.25 cm (
) , and a -2.24-σC charge (
) is located at y=-1.80 cm (
).
The total electric potential at the origin is
.
How to calculate the total electric potential at the origin?
The total electric potential at some point due to several point charges is represented by:

Here,
(Columbic constant)
The total electric potential at point
is the sum of the potentials due to
and
will be:

Substituting the values, we get:

Hence, the total electric potential at the origin is
.4
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Answer:
152642.2
Explanation:
the pressure at the bottom of the cylinder is
P = Po + rho gh
=101300+806(9.8)(6.5)
=152642.2 Pa
Answer:
difference in flight time= 0.3023 hour
Explanation:
The question is incomplete, but I found it in your textbook.
Spped of aircraft = 850 km/h
Opposing speed of wind = 90km/h
Hence, the net speed when it's travelling west = 850 - 90 = 760 km/hr
The distance covered = 1200km
time taken = distance/ time = 1200/ 760 = 1.5789 hours
When coming back, the speed of the wind is complementary to the speed of the aircraft so
net speed when it's coming back = 850 +90 = 940 km/hr
time taken in this instance = 1200/ 940 = 1.2765 hours
Hence, the difference in flight time= 1.5789 - 1.2765 = 0.3023 hour
The net force is (40 Newtons) (down the road).
But 40 Newtons is not going to move a piano very enthusiastically.
If the frequency is large then the period is short and if the frequency is small then the period is long