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3 years ago

What measure remains consistent no matter its location

Chemistry

2 answers:

Shalnov [3]3 years ago

7 0

Mass remains consistent everywhere, it doesnt change

Komok [63]3 years ago

6 0

Mass is the measure that remains consistent no matter its location.

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Where did the longest tsunami form?

max2010maxim [7]

July 9, 1958: in Lituya Bay, Alaska was caused by a landslide triggered by an 8.3 magnitude earthquake.

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3 years ago

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Why do nitrogen and oxygen form negative ions, not positive ones, in simple binary compounds.

gavmur [86]

Answer:

it is easier for them to have an octet of electrons(8e)

Each ion will: obtain the noble gas structure, each atom has high ionization energy

Explanation:

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2 years ago

Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production

Lynna [10]

Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

(1) C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

(2) CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

(3) H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

(4) C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

(5) CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = -747.54kJ

Thus ΔH° of the reaction is -747.54kJ

3 0

3 years ago

Calculate the mass percent by volume of 330.1 g of glucose (C₆H₁₂O₆, MM = 180.2 g/mol) in 325 mL of solution.

nadezda [96]

Answer: The mass percent by volume is 101.6%

Explanation:

The solution concentration expressed in percent by volume means that the amount of solute present in 100 parts volume of solution.

It is represented in formula as :

mass percent by volume = $\frac{\text {mass of solute}\times 100}{\text {Volume of solution in ml}}\%$

Given : mass of glucose = 330.1 g

volume of solution = 325 ml

Thus mass percent by volume = $\frac{330.1g\times 100}{325ml}=101.6\%$

Thus the mass percent by volume is 101.6%

3 0

3 years ago

PLEASEEEEEE HELPPPP???

Elenna [48]

1. c
2. a
3. a
(I’m not 100% but 2 & 3 couldn’t be transform)

4 0

3 years ago