Answer:
Explanation:
let t be time since the second diamond is released
a) y = ½g(t + 1)²
b) y' = ½g(t)²
c)
25 = ½g(t + 1)² - ½gt²
25 = ½g(t² + 2t + 1) - ½gt²
25 = ½gt² + gt + ½g - ½gt²
25 = g(t + ½)
t + ½ = 25 / g
t = (25 / g) - ½
t = (25 / 9.8) - ½
t = 2.05102... ≈ 2.1 s
Answer:
The gallon of milk is placed at a distance of 0.641 meters.
Explanation:
We have,
Mass of two 0.6 kg cartons of cereal is 1.2 kg
Length of the basket, l = 0.77 m
Center of the basket is 0.385 m
Mass of the half gallon of milk is 1.8 kg
Total weight in the basket is 1.2 + 1.8 = 3 kg
We need to find the position of the gallon of milk so that the center of mass (COM) of your groceries is at the center of the basket.
So,
(3 × 0.385) = (1.2 × 0) + (1.8 × x)
1.155 = 1.8 x
x = 0.641 meters
So, the gallon of milk is placed at a distance of 0.641 meters.
Answer:
Distance s = 90 meter
Explanation:
Given:
Initial velocity u = 0 m/s
Final velocity v = 30 m/s
Acceleration a = 5 m/s²
Find:
Distance s
Computation:
v² = u² + 2as
30² = 0² + 2(5)(s)
Distance s = 90 meter
