Answer:
H3PO4 Mol mass..
= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.
a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.
b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.
c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.
(Total = 100% H3PO4).
Explanation:
Find the molar mass of all the elements in the compound in grams per mole.
Find the molecular mass of the entire compound.
Divide the component's molar mass by the entire molecular mass.
You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
Answer:
The energy needed to split an atom into separate protons, neutrons, and electrons
Explanation:
The equation E = MC^2 is developed by Einstein’s Special Relativity Theory
where,
E = Energy
M = mass
C = speed of the light
The energy should be measured in Joules i.e J
The mass should be measured in Kilogram i.e Kg
And, the speed of the light should be measured in meters per second i.e ms-1
The C should be squared
Now the energy is required to divided into three particles i.e protons, electrons and neutrons
It also needs to allocate the nucleus into distinct protons and neutrons that we called binding energy of nuclear
And if the energy is required to take off an electron from an atom we called the energy of ionization
And if the energy is required to add an electron to an atom so we called it affinity of electron
I think the answer is yes
Answer:
1.2 M
Explanation:
Let's consider the following reversible reaction.
CuS(s) + O₂(g) ⇌ Cu(s) + SO₂(g)
To find the equilibrium concentration of O₂ we will use an ICE Chart. We will only consider gases and aqueous species since the activity of solids and liquids is 1.
CuS(s) + O₂(g) ⇌ Cu(s) + SO₂(g)
I 2.9 0
C -x +x
E 2.9-x x
The equilibrium constant (Kc) is:
![Kc=1.5=\frac{[SO_{2}]}{[O_{2}]} =\frac{x}{2.9-x} \\x=1.7](https://tex.z-dn.net/?f=Kc%3D1.5%3D%5Cfrac%7B%5BSO_%7B2%7D%5D%7D%7B%5BO_%7B2%7D%5D%7D%20%3D%5Cfrac%7Bx%7D%7B2.9-x%7D%20%5C%5Cx%3D1.7)
The concentration of O₂ at equilibrium is:
[O₂] = 2.9 -x = 2.9 - 1.7 = 1.2 M
