an animal refuge park has 120 gazelles.If the population increases by 5% in one year, how manu gazells will the park have next y
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The reaction that has been, following the law of conservation of mass has been .
The law of conservation has been given in the chemical reaction that there has been no loss or gain of the mass and energy.
The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.
<h3 /><h3>Conservation of mass in Cellular respiration</h3>
The following reactions have been identified as:
Carbon atoms
Reactant = 3
Product = 18
Oxygen atoms
Reactant = 9
Product = 18
Hydrogen atoms
Reactant = 6
Product = 36
The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.
Carbon atoms
Reactant = 6
Product = 6
Oxygen atoms
Reactant = 24
Product = 18
Hydrogen atoms
Reactant = 12
Product = 12
The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.
Carbon atoms
Reactant = 6
Product = 6
Oxygen atoms
Reactant = 18
Product = 18
Hydrogen atoms
Reactant = 12
Product = 12
The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.
Carbon atoms
Reactant = 6
Product = 0
Oxygen atoms
Reactant = 12
Product = 12
Hydrogen atoms
Reactant = 24
Product = 0
The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.
Thus, the reaction that has been following the law of conservation of mass has been .
Learn more about law of conservation, here:
Explanation:
The given data is as follows.
Temperature of dry bulb of air =
Dew point = = (10 + 273) K = 283 K
At the dew point temperature, the first drop of water condenses out of air and then,
Partial pressure of water vapor = vapor pressure of water at a given temperature
Using Antoine's equation we get the following.
= 0.17079
= 1.18624 kPa
As total pressure = atmospheric pressure = 760 mm Hg
= 101..325 kPa
The absolute humidity of inlet air =
= 0.00735 kg / kg dry air
Hence, air leaving the humidifier has a has an absolute humidity (%) of 0.07 kg / kg dry air.
Therefore, amount of water evaporated for every 1 kg dry air entering the humidifier is as follows.
0.07 kg - 0.00735 kg
= 0.06265 kg for every 1 kg dry air
Hence, calculate the amount of water evaporated for every 100 kg of dry air as follows.
= 6.265 kg
Thus, we can conclude that kg of water the must be evaporated into the air for every 100 kg of dry air entering the unit is 6.265 kg.