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telo118 [61]
3 years ago
7

Friction factor for fluid flow in pipe does not depend upon the A. pipe length. B. pipe roughness. C. fluid density & viscos

ity. D. mass flow rate of fluid.
Chemistry
1 answer:
Feliz [49]3 years ago
8 0

Answer:

C. fluid density & viscosity

Explanation:

In 1850, Darcy-Weisbach experimentally deduced an equation to calculate shear losses ("friction"), in a tube with permanent flow and constant diameter:

hf = (f x L x V^2) / (D x 2g)

where:

hf: shear losses

f:  shear loss factor (pipe roughness)

g: gravity acceleration

D: tube diameter

L: tube length  

V: fluid average speed in the tube

To calculate the loss factor “f” in the Poiseuille laminar region, he proposed in 1846 the following equation:

f = 64 / Re

Where:

Re: Reynolds number

The influence of the parameters on f is quantitatively different according to the characteristics of the current.

In any straight pipeline that transports a liquid at a certain temperature, there is a critical speed below which the regimen is laminar. This critical value that marks the transition between the two regimes, laminar and turbulent, corresponds to a Re = 2300, although in practice, between 2000 and 4000 the situation is quite inaccurate. Thus:

Re <2000: laminar regimen

2000 <Re <4000: critical or transition zone

Re> 4000: turbulent regime

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According to Dalton's law, the total pressure is the sum of individual pressures.

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p_{He}=211mmHg

Thus  the partial pressure of the helium gas is 211 mmHg.

b) According to the ideal gas equation:

PV=nRT

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R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= ?

n=\frac{PV}{RT}=\frac{0.28\times 13.0}0.0821\times 282}=0.157moles

Mass of helium= moles\times {\text {molar mass}}=0.157\times 4=0.629g

Thus mass of helium gas present in a 13.0-L sample of this mixture at 282 K is 0.629 grams

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