Answer:
the third one is incorrect
Explanation:
10 x 10³= 10^1 x 10^3 = 10^4
Answer:
Explanation:
Given that
Mass of bowling ball M1=7.2kg
The radius of bowling ball r1=0.11m
Mass of billiard ball M2=0.38kg
The radius of the Billiard ball r2=0.028m
Gravitational constant
G=6.67×10^-11Nm²/kg²
The magnitude of their distance apart is given as
r=r1+r2
r=0.028+0.11
r=0.138m
Then, gravitational force is given as
F=GM1M2/r²
F=6.67×10^-11×7.2×0.38/0.138²
F=9.58×10^-9N
The force of attraction between the two balls is
F=9.58×10^-9N
Answer: Given mass of man = 85kg
Distance crate was pushed = 4m
Force exerted on crate = 500N
Angle inclined = 20°
Let Total force exerted Ft = (mg * sin(20)) + 500
Ft =( 85*9.81* sin20°) + 500
Ft = 758N
Work done Wd = Ft * distance
Wd = 785 * 4 = 3.14 * 10^3J
Refer to the diagram shown below.
The component of the applied force perpendicular to the door is
F * sin(60°) = 0.866F N
Because the moment arm is 0.40 m, the torque is
(0.866F N)*(0.4 m) = 0.3464F N-m
This torque is equal to 1.4 N-m, therefore
0.3464F = 1.4
F = 4.04 N
Answer: 4.04 N