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ASHA 777 [7]
3 years ago
14

What is the internal resistance of an automobile battery that has an emf of 12.0 V and a terminal voltage of 18.4 V while a curr

ent of 7.20 A is charging it?
Physics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

0.888 ohm

Explanation:

We have given that the battery has an emf of 12 volt that E =12 volt

Terminal voltage V =18.4 volt

Current through the battery is =7.20 A

We have top find the internal resistance of the battery

Now according to Kirchhoff's law V=E+IR

So R=\frac{V-E}{I}=\frac{18.4-12}{7.2}=0.888\ ohm

So the value of internal resistance of battery is 0.888 ohm

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Explanation:

In an adiabatic process, when gases are compressed, work is done on the liquid and the temperature increases

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Phase unbalance causes three-phase motors to operate at temperatures ? and, therefore, the motor cannot deliver its rated horsep
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Phase unbalance causes three-phase motors to operate at temperatures higher than nameplate ratings and, therefore, the motor cannot deliver its rated horsepower.

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An EV stands for an electric vehicle. Electric vehicles (EVs) are autos that are powered totally or partially by electricity.

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1 year ago
At what time of year is the intensity of solar radiation striking each of earth's hemispheres weakest?
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5 0
3 years ago
A missile is moving 1350 m/s at a 25.0° angle. It needs to hit a target 23,500 m away in a 55.0° direction in 10.20 s. What is d
QveST [7]

Answer:

  The target's velocity is about 1320 m/s in the direction 265.7°.

Explanation:

In order for there to be a collision between missile and target, we must have ...

  (target starting position) + (target movement) = (missile movement)

assuming the missile starts from the origin of all measurements. The missile moves 10.2 seconds before impact, so moves a distance of ...

  (10.2 s)(1350 m/s) = 13,770 m

__

We are interested in the target movement, so we can solve for that:

  (target movement) = (missile movement) - (target starting position)

In terms of meters, this is ...

  (target movement) = 13770∠25° - 23500∠55° ≈ 13467.74∠-94.3°

The target covers this distance in the same 10.2 seconds before collision, so its speed is (13467.74 m)/(10.2 s) ≈ 1320.4 m/s.

As a positive angle, the target's direction is ...

  -94.3° +360° = 265.7°

The direction of the target's velocity is 265.7°.

_____

If you're calculating this by hand, there are a couple of ways you can do it. You can convert to rectangular coordinates and back (perhaps least confusing), or you can use the law of cosines to solve the triangle, then translate angles back to the x-y coordinate plane.

Using rectangular coordinates, we have ...

  13770∠25° = 13770(cos(25°), sin(25°)) ≈ (12479.9, 5819.45)

  23500∠55° = 23500(cos(55°), sin(55°)) ≈ (13479.0, 19250.1)

Then the difference is ...

  (12479.9, 5819.45) -(13479.0, 19250.1) ≈ (-999.188, -13430.6)

and the (3rd-quadrant) angle is ...

  target direction = arctan(-13430.6/-999.188) ≈ -94.3° = 265.7°

__

The target's speed is found by dividing the distance it covers by the time it takes.

  √(13430.6² +999.188²)/10.2 ≈ 1320.36 . . . m/s

3 0
3 years ago
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