PLEASE HELP! 50 points and brainlyist to the correct answers!

Can atoms combine in different ways to make up all of the substances you encouter every day

qaws [65]

Majority can such as hydrogen H and oxygen O forming water H2O but uranium having extra neutrons to form plutonium and beyond simply can't because it will not last for a fraction of a second or spiral out of control and violently react like the little boy and the fat man (a uranium and plutonium nuclear weapon) so yes and no

8 0

3 years ago

1. Una onda tiene una longitud de onda de 2 metros y una frecuencia de 1.5 Hz. ¿Cuál es su velocidad?

IrinaVladis [17]

Answer:

3 m/s

Explanation:

▲

usando la fórmula velocidad = frecuencia multiplicada por la longitud de onda.

v = (1.5)(2)

v= 3 m/s

6 0

3 years ago

Which solution has the same boiling point as 0.25 mol CaCl2 dissolved in 1000 g water?

Rufina [12.5K]

The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality).

ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
 ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 °C
 ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 °C
 ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 °C
 ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 °C

Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.

5 0

3 years ago

What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t

Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

Step 1: Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

Step 2: The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ

Step 3: Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

Step 4: Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

Step 5: Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0

3 years ago

I have a buddy who recycles electronics, and isolates metals from the connector pins electrical boards. He isolates gold, for ex

Kisachek [45]

Answer:

Theoretical yield = 3.75g

Explanation:

Percent yield is defined as one hundred times the ratio between actual yield and theoretical yield. The expression is:

Percent yield = Actual Yield / Theoretical Yield * 100

In the problem, your actual yield was 3-00g.

Percent yield is 80.0%.

Solving for theoretical yield:

80% = 3.00g / Theoretical yield * 100

Theoretical yield = 3.00g / 80.0% * 100

<h3>Theoretical yield = 3.75g</h3>

3 0

3 years ago