Answer:
Explanation:
<u>1) Balanced chemical equation:</u>
<u>2) Mole ratio:</u>
- 2 mol S : 3 mol O₂ : 2 mol SO₃
<u>3) Limiting reactant:</u>
n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂
n = 7.0 g / 32.065 g/mol = 0.2183 mol S
Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859
Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5
Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.
<u>4) Calcuate theoretical yield (using the limiting reactant):</u>
- 0.1875 mol O₂ / x = 3 mol O₂ / 2 mol SO₃
- x = 0.1875 × 2 / 3 mol SO₃ = 0.125 mol SO₃
<u>5) Yield in grams:</u>
- mass = number of moles × molar mass = 0.125 mol × 80.06 g/mol = 10.0 g
<u>6) </u><em><u>Percent yield:</u></em>
- Percent yield, % = (actual yield / theoretical yield) × 100
- % = (7.9 g / 10.0 g) × 100 = 79%
4X + 3O₂ = 2X₂O₃
n(X₂O₃)=0.02225 mol
m(X)=4.000 g
x - the molar mass of metal
m(X)/4x=n(X₂O₃)/2
x=m(X)/{2n(X₂O₃)}
x=4.000/{2*0.02225)=89.89 g/mol
X=Y (yttrium)
This type interaction is called the London dispersion force. These are temporary forces that happens when electrons of two adjacent atoms occupy positions that will result to temporary dipoles. The constant motion of the electrons will cause to form an instantaneous dipole when the electrons are unsymmetrically distributed. These forces are present in nonpolar substances.
The element with the lowest melting point is Ga.
Hence, Option (C) is correct answer.
<h3>What is Melting point ?</h3>
Melting point is usually defined as the temperature at which solid changes to liquid.
<h3>What is the order of melting point of B, Al, Ga, Tl ?</h3>
The melting point order of B, Al, Ga, Tl is B > Al> Tl > Ga due to structural changes, melting point increases from Ga to Tl. Hence Ga has the lowest melting point among all these.
Thus from the above conclusion we can say that The element with the lowest melting point is Ga.
Hence, Option (C) is correct answer.
Learn more about the Melting Point here: brainly.com/question/40140
#SPJ4
