Density = 0.7899 g/mL
mass = 28.7 g
Volume = ?
therefore:
D = m / V
0.7899 = 28.7 / V
V = 28.7 / 0.7899
V = 36.333 mL
Answer:
crushes the ice to compaction and satasfation
Answer : The molarity of the chloride ion in the water is, 5.75 M
Explanation :
As we are given that 16.6 % chloride ion that means 16.6 grams of chloride ion present 100 grams of solution.
First we have to calculate the volume of solution.


Now we have to calculate the molarity of chloride ion.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :

Now put all the given values in this formula, we get:

Thus, the molarity of the chloride ion in the water is, 5.75 M
Im pretty sure it would also be 25
To answer this question, we need to convert the given number of moles of the compound copper (II) cyanide to grams by multiplying the compound's molar mass. The molar mass of copper (II) cyanide is 115.55 g/mol. Multiply 4 by this number, the answer is 462.2 grams.