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Travka [436]
3 years ago
11

What is the frequency of a wave if the speed is 4300 m/s and the wavelength is 32 m?

Physics
1 answer:
givi [52]3 years ago
8 0
4300 they didn’t look alike because DJ sinwosnbube is wow
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Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface. When she lands on Noveria, a distant planet in
Anastasy [175]

Answer:

Acceleration of gravity on Noveria = 4.4 m/s²

Explanation:

Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface.

We have weight, W = mg

Acceleration due to gravity, g = 9.81m/s²    

799 = m x 9.81

Mass of Shepard, m = 81.45 kg            

She lands on Noveria, a distant planet in our galaxy, she weighs 356 N.

We have weight, W = mg'

                 356 = 81.45 xg'

Acceleration of gravity on Noveria, g' = 4.4 m/s²

6 0
4 years ago
8) Calculate the kinetic energy of a truck that has a mass of 6100 kg and is moving at 55 m/s.
Inessa [10]

Answer:

<h2>9,226,250 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

v is the velocity

m is the mass

From the question we have

k =  \frac{1}{2}  \times 6100 \times  {55}^{2}  \\  = 3050 \times 3025 \\  = 9226250

We have the final answer as

<h3>9,226,250 J</h3>

Hope this helps you

7 0
3 years ago
In nuclear reaction 5 kg of reactants give 2kg of products
dlinn [17]
Choice A is correct.======Kinetic energy equation:   KE = (1/2)(m)(v²)This tells us that KE is directly proportional to mass and the square of velocity. In other words, the more mass and more velocity an object has, the more kinetic energy.If an object is sitting at the top of a ramp, there is no velocity and therefore no kinetic energy.    Choices B and D are wrong.A golf ball has more mass than a ping-pong ball, so a ping-pong ball would have less kinetic energy than a golf ball rolling off the end of a ramp.    Choice C is wrong.Choice A is correct.


6 0
3 years ago
Racing cars driven by chris and kelly are side by side at the start of a race. the table shows the velocities of each car (in mi
Mamont248 [21]

Solution

distance travelled by Chris

\Delta t=\frac{1}{3600}hr.

X_{c}= [(\frac{21+0}{2})+(\frac{33+21}{2})+(\frac{55+47}{2})+(\frac{63+55}{2})+(\frac{70+63}{2})+(\frac{76+70}{2})+(\frac{82+76}{2})+(\frac{87+82}{2})+(\frac{91+87}{2})]\times\frac{1}{3600}

=\frac{579.5}{3600}=0.161miles

Kelly,

\Delta t=\frac{1}{3600}hr.

X_{k}=[(\frac{24+0}{2})+(\frac{3+24}{2})+(\frac{55+39}{2})+(\frac{62+55}{2})+(\frac{71+62}{2})+(\frac{79+71}{2})+(\frac{85+79}{2})+(\frac{85+92}{2})+(\frac{99+92}{2})+(\frac{103+99}{2})]\times\frac{1}{3600}

=\frac{657.5}{3600}

\Delta X=X_{k}-X_{C}=0.021miles

4 0
3 years ago
When you ask you friend for hoemwork answers and he answers like a year later hahahah
Hitman42 [59]
G that’s a nice friend
5 0
3 years ago
Read 2 more answers
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