Do frictional forces act in the same direction or in the opposite direction to the applied force?

1 answer:

3 0

Frictional forces act in the direction opposite to the MOTION. That direction could be the same OR opposite to applied force.

-- If you push a loaded heavy wagon from behind, trying to get it going faster, friction is acting against you, opposite to your force.

-- If you push a loaded rolling heavy wagon from in front, trying to make it slow down, friction is acting with you, in the same direction as your force.

-- Opposite to the motion both times.

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A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of

Fittoniya [83]

The acceleration of the air plane is $3.879 \mathrm{m} / \mathrm{s}^{2}$

<u>Explanation:</u>

Given:

The mass of the air plane = 1492.3 kg

Force of each four engine = 1447.5 N

So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N

The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

$\text {Force }(F)=m \times \text { acceleration }(a)$

The above equation can be written as below to find acceleration,

$a=\frac{F}{m}$

Now. Substitute the given values, we get,

$a=\frac{5790}{1492.3}=3.879 \mathrm{m} / \mathrm{s}^{2}$

3 0

3 years ago

A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds

vichka [17]

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

$\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega = (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s$