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nikitadnepr [17]
3 years ago
7

How did the formation of natural gas and oil differ from the formation of coal?

Physics
1 answer:
ivann1987 [24]3 years ago
6 0

Explanation:

Coal and natural gases are fossil fuels that are found in geologic formation. They both form under similar environment of high temperature and pressure which transforms organic matter.

Natural gas is a fluid and coal is a solid.

How did they form differently?

  • Natural and gas and petroleum are both derived from an organic matter rich in both plant and animal remains.
  • Coal is typically derived from organic matter that is rich in only plant remains usually formed in swampy area.

Learn more:

Coal brainly.com/question/10055728

#learnwithBrainly

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zimovet [89]

The old style (incandescent) light bulb converts more energy
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How do mechanical waves compare with electromagnetic waves?
Naddika [18.5K]

Answer:

Main Difference Between Mechanical and Electromagnetic waves

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Electromagnetic waves can travel through a vacuum, that is an empty space, whereas mechanical waves cannot. They need a medium to travel such as water or air. Ripples in a pond are an example of mechanical waves whereas electromagnetic waves include light and radio signals, which can travel through the vacuum of space.

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                                                                            Have a wonderful day!

                                                                                                ~Lillith of brainly~

6 0
2 years ago
A light wave moves from diamond (n= 2.4) into water (n= 1.33) at an angleof 24°. what angle does it have in water?
worty [1.4K]

Answer:

n1 sin θ1 = n2 sin θ2      Snell's Law       (θ1 is the angle of incidence)

sin θ2 = n1 / n2 * sin θ1

sin θ2 = 2.4 / 1.33 * sin θ1

sin θ2 = 1.80 * .407 = .734

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3 0
2 years ago
PLEASE PLEASE PLEASE A mad scientist places massive amounts of charge on basketball sized aluminum balls. The charge on the ball
bazaltina [42]

Answer:

4.2 x 10⁷N

Explanation:

Given parameters:

Charge on ball:

             q₁  = 3C

              q₂ = 14C

Distance between balls  = 9000m

Unknown:

Force acting on the two balls

Solution:

The force experienced by the two charges is given by coulombs law. It is mathematically expressed as;

                      F  = \frac{k q_{1} q_{2} }{r^{2} }

where k  = 9 x 10⁹Nm²/C²

           q is the charges

             r is the distance

Input the variables and solve;

                 

        F  = \frac{9 x 10^{9} x 3 x 14 }{9000}  = 4.2 x 10⁷N

8 0
3 years ago
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