Question

When Karl Kaveman adds chilled grog to his new granite mug, he removes 10.9 kJ of energy from the mug. If it has a mass of 625 g and was at 25°C, what is its new temperature? Specific heat capacity of granite = 0.79 J/(g·K)

Answer 1

Answer:

3°C

Explanation:

We can that heat Q=m$c_p$ dT

Where m is the mass $c_p$ = specific heat capacity

dT = Temperature difference

here we have given m=625 g =.625 kg

specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)

$T_1$ =25°C

$T_2$ we have to find

we have also given Q=10.9 KJ

10.9=0.625×0.79×(25-$T_2$)

25-$T_2$ =22

$T_2$=3°C

Answer 2

Answer:

47.08 degree C

Explanation:

H = 10.9 kJ = 10.9 x 1000 J

m = 625 g = 0.625 kg

T1 = 25 degree C

Let the final temperature is T2.

c = 0.79 J/g C = 790 J/kg C

H = m x c x (T2 - T1)

10.9 x 1000 = 0.625 x 790 x  (T2 - 25)

T2 = 47.08 degree C