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2 years ago

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A 1000-kilogram car traveling due east at 15 meters per second hit from behind and receives a forward impulse of 6000 newton-sec

onds. Determine the magnitude of the car's change in momentum due to this impulse.

1 answer:

strojnjashka [21]2 years ago

8 0

The change in momentum of the car is 6000 kg m/s

Explanation:

According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on the object, therefore:

$\Delta p = I$

where

$\Delta p$ is the change in momentum

I is the impulse exerted

For the car in this problem, the impulse received is

I = 6000 kg m/s (in the forward direction)

Therefore, the change in momentum of the car is equal to this value:

$\Delta p = I = 6000 kg m/s$ (in the forward direction)

We can also calculate what is the new momentum of the car. In fact, the initial momentum is

$p_i = mu = (1000 kg)(15 m/s)=15,000 kg m/s$

And so, the new momentum is

$p_f = p_i + \Delta p = 15,000 + 6,000 = 21,000 kg m/s$

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

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