Ask question

Ask question

All categories

3 years ago

8

What often happens to light when it travels from one medium to another

1 answer:

quester [9]3 years ago

3 0

Answer:

Although the speed changes and wavelength changes, the frequency of the light will be constant. The frequency, wavelength, and speed are related by: The change in speed that occurs when light passes from one medium to another is responsible for the bending of light, or refraction, that takes place at an interface.

Explanation:

You might be interested in

Monochromatic light (vacuum = 612 nm) shines on a soap film (n = 1.33) that has air on either side of it. The light strikes the

weeeeeb [17]

Answer:

t = 110.079 nm

Explanation:-

we know that

for constructive interference in thin film

2nt = (m + (1/2))λ

where, n is refractive index

for minimum thickness m =0

2nt = λ /2

thickness t = λ / 4n

Here

wavelength of light, λ = 612*10^{-9} m

refractive indices = 1.393 $t = \frac{(612*10^{-9})}{(4*1.33)}$ $t = 115.03*10^{-9} m$

t = 110.03 nm

4 0

2 years ago

How do you calculate the speed of a 3.1eV photon and a 3.1eV electron?

-Dominant- [34]

Explanation:

We need to find the speed of a 3.1eV proton and a 3.1eV electron.

For proton, using conservation of energy such that,

$\dfrac{1}{2}m_pv_p^2=eV\\\\v_p^2=\dfrac{2eV}{m_p}\\\\v_p=\sqrt{\dfrac{2eV}{m_p}}$

$m_p$ is mass of proton

$v_p=\sqrt{\dfrac{2\times 3.1\times 1.6\times 10^{-19}\ J}{1.67\times 10^{-27}\ kg}}\\\\v_p=2.43\times 10^5\ m/s$

For electron,

$\dfrac{1}{2}m_ev_e^2=eV\\\\v_e^2=\dfrac{2eV}{m_e}\\\\v_e=\sqrt{\dfrac{2eV}{m_e}}$

$m_e$ is mass of proton

$v_e=\sqrt{\dfrac{2\times 3.1\times 1.6\times 10^{-19}\ J}{9.1\times 10^{-31}\ kg}}\\\\v_e=1.44\times 10^6\ m/s$

Hence, this is the required solution.

5 0

2 years ago

point) A tank in the shape of an inverted right circular cone has height 5 meters and radius 4 meters. It is filled with 4 meter

zysi [14]

Answer:

W = 907963.50 J = 907.96 J

Explanation:

Note: Refer to the figure attached

Now, from the figure we have similar triangles ΔAOB and ΔCOD

we have

$\frac{5}{4}=\frac{x}{r}$

or

$r=\frac{4x}{5}$

Now, the work done to empty the tank can be given as:

$W = \int\limits^4_0 {(5-x)\rho\times g A} \, dx$

or

$W = \int\limits^4_0 {(5-x)1080\times 9.8 (\pi r^2)} \, dx$

or

$W = \int\limits^4_0 {(5-x)\times10584\times (\pi (\frac{4x}{5})^2)} \, dx$

or

$W = 6773.76\pi\int\limits^4_0 {(5-x)x^2)} \, dx$

or

$W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0$

or

$W = 6773.76\pi[\frac{128}{3}]$

or

W = 907963.50 J = 907.96 J

7 0

2 years ago

What is a common noun?

Rainbow [258]

I HOPE IT WILL HELP YOU.

Thank you.

<u>TEDDYLOVER</u>

6 0

2 years ago

Which of the following is the flow of electrons through a wire or a conductor?

Sonja [21]

Explanation:

electric current is the answer

7 0

2 years ago