<span>37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2
4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
Answer: Temperature in constant pressure is 286 K
Explanation: If pressure remains constant, then V/T = constant.
V1 = 350 ml and T1 = 200 K and V2 = 500 ml. V1/T1 = V2/T2
and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K
X is usually representing time so years, days, etc
The acid dissociation constant of benzoic acid is 6.5 x 10^-5. Therefore, the pH of the benzoic acid solution prior to adding sodium benzoate is:
pH = -log[Ka]
pH = -log (6.5 x 10^-5)
pH = 4.19
The pH of the benzoic acid solution is 4.19 which is acidic, but a weak acid.
