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shusha [124]
3 years ago
15

Why did we use solid camphorsulfonic acid rather than aqueous h2so4?

Chemistry
1 answer:
Evgen [1.6K]3 years ago
3 0
Most common mineral acids solutions (HCl, H2SO4, HNO3, H3PO4, etc.) are prepared in water. Infact, system is<span> acidic only in aqueous medium.
</span>
However, in few cases, it isn't advisable/viable to perform reaction is aqueous medium. This can be due to poor solubility of reactant in water. This situation arises especially, if reactant is highly non-polar in nature.

There also exist a possibility that, reactant is not stable in aqueous medium. In such event, use of water has to be avoided.    

 For such reaction,  solid camphorsulfonic acid is added in reaction, when acid is required to initiate/catalyst the reaction.

The major advantage that camphorsulfonic acid offers is that, it is solid and hence it is easy to weight. Also, they don't required water addition for the reaction.
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aev [14]

Answer:

D. Weathering includes the transportation of sediment while erosion does not.

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3 years ago
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When performing a Friedel-Crafts alkylation reaction, not only does one have the problems of multiple alkylation and rearrangeme
3241004551 [841]

Strong electron withdrawing groups prevents Friedel Crafts reaction because when a withdrawing group attracts the electrons decrease the availability of the electronic pair and the enough electronic density of it in order to make possible the aromatic electrophilic substitution.

Strong electron donating groups like NH2 doesn’t undergo Friedel Crafts reaction because NH2 is a Lewis base that means an electron donor. Due to Friedel Crafts reaction is an acid base reaction, the AlCl3 will be attacked by the lone pair available from NH2 producing a salt. The same occurs with phenol because the lone pair of electrons available in the OH group so Friedels Crafts doesn’t undergo with benzene attached to the strong electron donating groups NH2 or OH.

3 0
4 years ago
What are the spectator ions in this equation?
dangina [55]

The given question is incomplete. The complete question is :

What is the net ionic equation for the following reaction?

H_2CrO_4+Ba(OH)_2

Answer : The spectator ions are Ba^{2+} and CrO_4^{2-}

Explanation:

Neutralization is a chemical reaction in which an acid and a base reacts to form salt and water.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

2H^+(aq)+CrO_4^{2-}(aq)+Ba^{2+}(aq)+2OH^-(aq)\rightarrow Ba^{2+}(aq)++CrO_4^{2-}(aq)+H_2O(l)

The ions which are present on both the sides of the equation are barium and chromate ions. and hence are not involved in net ionic equation.

Hence, the net ionic equation is H^++OH^-\rightarrow H_2O

6 0
4 years ago
I just have toooooo.......
lesantik [10]
Hi there
cool photo

thanks for the points and have a wonderful day :)
7 0
3 years ago
Read 2 more answers
Metal rings can be coated with a layer of copper using electricity.
Eduardwww [97]

<u>First of all, what is electrolysis?</u>

Electrolysis is the process of breaking down ionic substances using direct current.

<u>Important points about electrolysis </u>

→ Ionic substances contain particles called ions.

→ Electricity is the flow of electrons or ions. For electrolysis to work, the compound must contain ions. The ions must be free to move for electrolysis to occur and it can happen by melting or dissolving an ionic substance in water.

→ Positively charged ions move to the negative electrode. They receive electrons and are <em>reduced</em>. The positive ions move towards the negative electrode because they want to cancel each other out.

→ Negatively charged ions move to the positive electrode.  They lose electrons and are <em>oxidised</em>. The substance that is broken down is called the electrolyte <em>(an electrolyte is just a liquid or solution that can conduct electricity)</em> . The negative ions move towards the positive electrode because they want to cancel each other out.

<h3>Cathode = Negative electrode</h3><h3>Anode = Positive electrode</h3>

Metal ions form at the cathode and non-metal ions form at the anode

How I remember if an element is <em>oxidised</em> or <em>reduced</em> is by remembering OIL RIG

OIL = Oxidation is Loss (of electrons)

RIG = Reduction is Gain (of electrons)

<h2><em><u>The answer to your question</u></em></h2>

1) The first step would be to clean the metal ring and sand it down because when the metal atoms from the electrolyte are deposited onto the ring, they will form a weak bond and they may simply 'fall' off. Also this could affect conductivity and the whole experiment. The more things you do accurately now, the more accurate your result will be.

2) You want to put the solution you are given in to the tank your going to be using.

3) This is basically the main part, you want to set up the circuit, I have attached a diagram at the bottom to show you the circuit. The copper rod will be the anode and the metal ring will be a cathode (ignore the elements).

4) Now turn on the circuit and you will start to see the solution spilt with the the solution now being split some going to the anode and some going the cathode.

5) Then a thin layer should form on the electrode.

Hope this helps :)

<h2><em><u></u></em></h2>

<em><u></u></em>

5 0
3 years ago
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