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3 years ago

What is a soundwave please quick

1 answer:

5 0

In physics, sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain.

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At sunrise two old women started to walk towards each other. one started from point a and went towards point b while the other s

konstantin123 [22]

Let the distance between points a and b = d

For the women starting from a her velocity be $V_1$ and for the women starting from b her velocity be $V_2$

Let the rising time of sun = x AM

We have $V_1$ = $\frac{d}{12+4-x}$

and we also have $V_2$ = $\frac{d}{12+9-x}$

At they meet means, they both travel a combined distance of d

So we have $V_1*(12-x)+V_2*(12-x)=d$

Substituting velocity values we will get

$\frac{d}{12+4-x}*(12-x)+\frac{d}{12+9-x}*(12-x)=d\\ \\ \frac{12-x}{12+4-x}+\frac{12-x}{12+9-x}=1\\ \\ \frac{12-x}{16-x}+\frac{12-x}{21-x}=1\\ \\ 252-21x-12x+x^2+192-12x-16x+x^2=336-16x-21x+x^2\\ \\ x^2-24x+108=0\\ \\ (x-6)(x-18)=0\\ \\$

x= 6 AM or 18 AM, but 18 AM is not possible,

Sun rise time is 6 AM

3 0

3 years ago

A cycle travels along a circular track of diameter 42 m. Calculate the distance travelled and the displacement of the cycle in (

DENIUS [597]

Answer:

(a) i) The distance travelled by the cycle in half round is approximately 65.97 m

ii) The displacement is 42 m

(b) (i) The distance travelled in one round is approximately 131.95 m

(ii) The displacement of the cycle in one round is 0

Explanation:

The diameter of the track through which the cycle travels, D = 42 m

(a) i) Half round is the motion of half the length of the circular path

The distance travelled by the cycle in half round = The length of half the circular track = (1/2) × π × D

∴ The distance travelled by the cycle in half round = (1/2) × π × 42 m = 21·π m ≈ 65.97 m

ii) The displacement half round = The change in the location of the cycle = The difference between the start and stop locations of the cycle on a straight line after half round

The angle at the center of the circular path the cycle turns in half round = 180°

Therefore, the path between the start and stop location of the cycle in half round = The diameter of the circular track

The displacement of the cycle in half round = The diameter of the circular track = 42 m

(b) (i) The distance travelled in one round = The perimeter of the circular track = π·D

∴ The distance travelled in one round = π × 42 m ≈ 131.95 m

(ii) The displacement of the cycle in one round = The change in the location of the cycle

The start and stop location of the cycle after moving one round is the same, therefore, there is no change in the location of the cycle.

Therefore we have;

The displacement of the cycle in one round = 0 (no change in location of the cycle)

7 0

3 years ago

3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P

KIM [24]

Answer:

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

$E=\frac{F}{Q}$

But the force F

$F= \frac{kQ1Q2}{r^2}$

But the electric field intensity due to a point charge Q at a distance r meters away is given by

$E= \frac{\frac{kQ1Q2}{r^2}}{Q} \\\\\E= \frac{Q1}{4\pi er^2 }$

From the relation above we can conclude that the as the distance between the two plate increases the electric field strength decreases

6 0

3 years ago

Which of the following is not a metric base unit? * Meter Liter Inch Gram

polet [3.4K]

Answer:

Liter

Explanation:

8 0

3 years ago

Read 2 more answers

When you push on an object such as a wrench, a steel pry bar, or even the outer edge of a door, you produce a torque equal to th

Korvikt [17]

Since youc oncetrate all your force directly towards the moment arm it means that you push it at an angle of your force is directed to the left or the right and I bet that it must be 90 degrees to the bar. Obviuosly, if you are about to push it you will do it straight up but not in a zig zag way. In other words, it should be perpendicular to the arm because the torque can be produced only if force is applied at a constant index (90).
Hope that helps! Regards.

5 0

3 years ago