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3 years ago

Consider the following unbalanced redox reaction:

Chemistry

1 answer:

Greeley [361]3 years ago

4 0

Answer:

Two

Explanation:

I believe your unbalanced equation should be

H₂O₂ + I₂ ⟶ IO₃⁻

The half-reactions and the overall reaction are:

5 × [H₂O₂ + 2H⁺ +2e⁻ ⟶ 2H₂O]

1 × <u>[ I₂ + 6H₂O ⟶ 2IO₃⁻ + 12H⁺ + 10e⁻] </u>

5H₂O₂ + I₂ ⟶ 2IO₃⁻ + 2H⁺ + 4H₂O

The reaction needs two hydrogen ions for balancing.

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Name three sources of atmospheric carbon dioxide.

quester [9]

The answer is decomposition, ocean release and respiration. hope this helps u :D

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3 years ago

Cylinder of air at 1.5 atm of pressure is kept at room temperature while a piston compresses the air from 40 l down to 10 ml. wh

djyliett [7]

The new pressure, P₂ is 6000 atm.

<h3>Calculation:</h3>

Given,

P₁ = 1.5 atm

V₁ = 40 L = 40,000 mL

V₂ = 10 mL

To calculate,

P₂ =?

Boyle's law is applied here.

According to Boyle's law, at constant temperature, a gas's volume changes inversely with applied pressure.

PV = constant

Therefore,

P₁V₁ = P₂V₂

Put the above values in the equation,

1.5 × 40,000 = P₂ × 10

P₂ = 1.5 × 4000

P₂ = 6000 atm

Therefore, the new pressure, P₂ is 6000 atm.

Learn more about Boyle's law here:

brainly.com/question/23715689

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2 years ago

A scientist has a container with a substance inside. At first, the molecules in the substance move away from each other. Later,

ArbitrLikvidat [17]

The answers here is B) Before, the substance was a gas, later it was a liquid.

Gas particles move freely and away from each other. However, liquid particles move around each other.

Hope this helps! :)(

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3 years ago

What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?

Lubov Fominskaja [6]

Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

$\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})$

Hence, the probability of finding the particle in the one-dimensional box is:

$P = \int_{x_{1}}^{x_{2}} \psi^{2} dx$

$P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx$

$P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx$

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

$P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]$

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})$

Solving for n=4:

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})$

$P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})$

$P = \frac{1}{8}$

I hope it helps you!

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3 years ago

In the following reaction, what element is gaining mass?

vagabundo [1.1K]

Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).

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3 years ago