The maximum height reached by the ball is 99.2 m
Explanation:
When the ball is thrown straight up, it follows a free fall motion, which is a uniformly accelerated motion with constant acceleration (
towards the ground). Therefore, we can use the following suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem, we have:
u = 44.1 m/s is the initial vertical velocity of the ball
v = 0 is the final velocity when the ball reaches the maximum height
s is the maximum height
is the acceleration of gravity (downward, so negative)
Solving for s, we find the maximum height reached by the ball:

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The period is the time taken by the wave to complete an oscillation. The frequency of the given sound is 500 Hz.
<h2>
Period:</h2>
It is the time taken by the wave to complete an oscillation. The frequency is inversely proportional to the time:

Where,
- frequency
- period = 0.002 s
Put the value in the equation,

Therefore, the frequency of the given sound is 500 Hz.
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Spreads out in the medium, first choice
Answer:
they r schooling fish
Explanation:
they need to be kept in groups of 5.
Answer:
The time taken for the ball to get to the batter is 0.41 s.
Explanation:
Given;
initial velocity of the baseball, u = 45 m/s
horizontal distance between the pitcher and the batter, X = 18.39 m
The horizontal distance or range of a projectile is given as;
X = ut
where;
t is the time of flight
u is the initial velocity
t = X / u
t = 18.39 / 45
t = 0.41 s
Therefore, the time taken for the ball to get to the batter is 0.41 s.