3 years ago

How can people reach their full potential?

Physics

1 answer:

PolarNik [594]3 years ago

6 0

If they have self motivation or others motivation, they will show their full potential.

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A satellite of Mars, called Phobos, has an orbital radius of 9.4 ✕ 106 m and a period of 2.8 ✕ 104 s. Assuming the orbit is circ

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Answer:

$6.27*10^{23}kg$

Explanation:

assume

M= mass of Mars

m=mass of phobos

r=orbital radius

T=period

we can apply F=ma to this orbital motion (considering the cricular motion laws)

where,

$F=\frac{GMm}{r^{2} }$ and a=rω^2

where ω= $\frac{2\pi }{T}$ and G is the universal gravitational constant.

G = 6.67 x 10-11 N m2 / kg2

$F=ma\\\frac{GMm}{r^{2} }=mr(\frac{2\pi }{T} )^{2}\\ M=\frac{r^{3}}{G} (\frac{2\pi }{T} )^{2}\\M=\frac{(9.4*10x^{6} )^{3}*(2\pi )^{2} }{(2.8*10^{4}) ^{2} *6.67*10^{-11} } \\M=6.27*10^{23}kg$

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Can we see the diagram? Thanks.

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The timeline below shows some major discoveries in biology.

34kurt

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Explanation:

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You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4

lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy $E=1.25\times10^{4}\ J$

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

Where, m = mass

c = specific heat

$\Delta T$ = temperature

Q = heat

Put the value into the formula

$c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}$

$c=14.8\ J/kg. K$

Hence, The samples specific heat is 14.8 J/kg.K

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B.) 70m is your answer!

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